Question

A person walking in high heals can damages the floor by making small dimples in the floor since all their weight is concentrated on the tip of the high heal. It the person weighs 81 kg and the high of the tip of the high heal is 3.5 cm2, what is the force over the floor?

Answer 1

Given :

Mass of person, m = 81 kg.

Area of high heal, A = 3.5 cm² = 0.00035 m².

To Find :

The pressure applied by the heal on the ground.

Solution :

We know, pressure is given by :

$P = \dfrac{mass}{Area}\\\\P = \dfrac{81}{0.00035} \ N/m^2\\\\P = 231428.57 \ N/m^2$

Hence, this is the required solution.