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makkiz [27]
3 years ago
5

Which particle rarely interacts with matter?

Physics
1 answer:
Marysya12 [62]3 years ago
4 0
D. Neutrino
Neutrinos are particles that rarely interact with matter.
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1) You slam on the brakes of your car in a panic, and skid a certain distance on a straight level road. If you had been travelin
aleksandr82 [10.1K]

Answer:

d = 4 d₀o

Explanation:

We can solve this exercise using the relationship between work and the variation of kinetic energy

         W = ΔK

In that case as the car stops v_f = 0

the work is

          W = -fr d

we substitute

          - fr d₀ = 0 - ½ m v₀²

           d₀ = ½ m v₀² / fr

now they indicate that the vehicle is coming at twice the speed

          v = 2 v₀

using the same expressions we find

           d = ½ m (2v₀)² / fr

           d = 4 (½ m v₀² / fr)

           d = 4 d₀o

3 0
3 years ago
Which of these is NOT a possible type of energy transformation?
Orlov [11]

to be franc i really think the answer is B

6 0
3 years ago
A beam of light has a wavelength of 4.5 x10^-7 meter in a vacuum. the frequency of this light is
valkas [14]
The basic relationship between frequency and wavelength for light (which is an electromagnetic wave) is
c= f \lambda
where c is the speed of light, f the frequency and \lambda the wavelength of the wave. 
Using \lambda=4.5 \cdot 10^{-7} m and c=3 \cdot 10^8 m/s, we can find the value of the frequency:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.7 \cdot 10^{14} Hz
3 0
3 years ago
If 100 kg person weighed 400 N on the planet Zorg,
Brut [27]

Answer:

<u>4 m/s²</u>

Explanation:

<u>Formula</u>

  • Weight = Mass x Gravity due to acceleration

<u>Solving</u> :

  • 400 N = 100 kg x g
  • g = 400/100
  • g = <u>4 m/s²</u>
5 0
2 years ago
Read 2 more answers
A passenger in a helicopter traveling upwards at 15 m/s accidentally drops a package out the window. If it takes 15 seconds to r
Alexeev081 [22]

Answer:

The helicopter was 1103.63 meters high when the package was dropped.

Explanation:

We consider positive speed as a downward movement

y: height (m)

t: time (s)

v₀: initial speed (m/s)

Δy = v₀t + \frac{1}{2}gt²

Δy= 15\frac{m}{s}×15 s + \frac{1}{2}×9.81\frac{m}{s^{2} }×(15 s)²

Δy= 1103.63 m

8 0
3 years ago
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