Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
Given the data in the question;
Hubble's constant; ![H_0 = 51km/s/Mly](https://tex.z-dn.net/?f=H_0%20%3D%2051km%2Fs%2FMly)
Age of the universe; ![t = \ ?](https://tex.z-dn.net/?f=t%20%3D%20%5C%20%3F)
We know that, the reciprocal of the Hubble's constant (
) gives an estimate of the age of the universe (
). It is expressed as:
![Age\ of\ Universe; t = \frac{1}{H_0}](https://tex.z-dn.net/?f=Age%5C%20of%5C%20Universe%3B%20t%20%3D%20%5Cfrac%7B1%7D%7BH_0%7D)
Now,
Hubble's constant; ![H_0 = 51km/s/Mly](https://tex.z-dn.net/?f=H_0%20%3D%2051km%2Fs%2FMly)
We know that;
![1\ light\ years = 9.46*10^{15}m](https://tex.z-dn.net/?f=1%5C%20light%5C%20years%20%3D%209.46%2A10%5E%7B15%7Dm)
so
![1\ Million\ light\ years = [9.46 * 10^{15}m] * 10^6 = 9.46 * 10^{21}m](https://tex.z-dn.net/?f=1%5C%20Million%5C%20light%5C%20years%20%3D%20%5B9.46%20%2A%2010%5E%7B15%7Dm%5D%20%2A%2010%5E6%20%3D%209.46%20%2A%2010%5E%7B21%7Dm)
Therefore;
![H_0 = 51\frac{km}{\frac{s}{Mly} } = 51000\frac{m}{s\ *\ Mly} \\\\H_0 = 51000\frac{m}{s\ *\ (9.46*10^{21}m)} \\\\H_0 = 5.39 *10^{-18}s^{-1}\\](https://tex.z-dn.net/?f=H_0%20%3D%2051%5Cfrac%7Bkm%7D%7B%5Cfrac%7Bs%7D%7BMly%7D%20%7D%20%3D%2051000%5Cfrac%7Bm%7D%7Bs%5C%20%2A%5C%20Mly%7D%20%20%5C%5C%5C%5CH_0%20%3D%2051000%5Cfrac%7Bm%7D%7Bs%5C%20%2A%5C%20%289.46%2A10%5E%7B21%7Dm%29%7D%20%5C%5C%5C%5CH_0%20%3D%20%205.39%20%2A10%5E%7B-18%7Ds%5E%7B-1%7D%5C%5C)
Now, we input this Hubble's constant value into our equation;
![Age\ of\ Universe; t = \frac{1}{H_0}\\\\t = \frac{1}{ 5.39 *10^{-18}s^{-1}} \\\\t = 1.855 * 10^{17}s\\\\We\ convert\ to\ years\\\\t = \frac{ 1.855 * 10^{17}}{60*60*24*365}yrs \\\\t = \frac{ 1.855 * 10^{17}}{31536000}yrs\\\\t = 5.88 *10^9 years](https://tex.z-dn.net/?f=Age%5C%20of%5C%20Universe%3B%20t%20%3D%20%5Cfrac%7B1%7D%7BH_0%7D%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B1%7D%7B%205.39%20%2A10%5E%7B-18%7Ds%5E%7B-1%7D%7D%20%5C%5C%5C%5Ct%20%3D%201.855%20%2A%2010%5E%7B17%7Ds%5C%5C%5C%5CWe%5C%20convert%5C%20to%5C%20years%5C%5C%5C%5Ct%20%3D%20%20%5Cfrac%7B%201.855%20%2A%2010%5E%7B17%7D%7D%7B60%2A60%2A24%2A365%7Dyrs%20%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B%201.855%20%2A%2010%5E%7B17%7D%7D%7B31536000%7Dyrs%5C%5C%5C%5Ct%20%3D%205.88%20%2A10%5E9%20years)
Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
Learn more: brainly.com/question/14019680
The candle flame releases hot gases, which directly go in upwards directions. Due to which the air near the flame of the candle is very hot and dense. The particles along with vapour move up. And since the sideways, the air is not very dense and hot, we are able to hold the candle. In anti-gravity region, there will be no density differences and also, the convection process wont occur. So, the candle quickly snuffs off.
Answer:
gas, metal
Explanation:
The three states of by which hydrogen is found in Jupiter is made up of:
- Gaseous hydrogen
- liquid hydrogen
- liquid metal hydrogen
This is also the same states found in Saturn too.
The pressure inside the largest planet in our solar system is very great.
- Hydrogen and helium makes up the entirety of the planet Jupiter.
- It has been discovered that inside this planet, hydrogen often occurs as gas, liquid and metal
- This is often attributed to the huge amount of pressure in the planet.
It would be either A or C if its still moving and not stopping
Explanation:
t = usin©/g
Where t is the time to reach the maximum height
Time spent in air is T = 2t
Hence, T = 2usin©/g
T = 2 x 20 x sin 65°/ 9.8
T = 3.69s