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allochka39001 [22]
3 years ago
7

To save fuel some truck drivers try to maintain a constant speed when possible a truck traveling at 26 km/h approaches a car sto

pped at a red light in the truck is 149.1 m from the car the light turns green in the car immediately begins to accelerate a 2.3 m/s squared how close does a truck come to the car assuming the truck does not slow down
Physics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Always do it on my own

So I gotta get through it

And the only thing I know

Is to love what I'm doing

Never give up, never slow

Till I finally prove it

Never listen to the no's

I just wanna keep moving

Keep my head up when I act

Head up, that's a fact

Never looking back

I'ma keep myself on track

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S_A_V [24]

Answer:

25

Explanation:

simple facts.

7 0
3 years ago
The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on
alekssr [168]

Answer:

The change in temperature is \Delta T  = 1795 K

Explanation:

From the question we  are told that

   The temperature coefficient is  \alpha  =  4 * 10^{-3 }\  k^{-1 }

The resistance of the filament is mathematically represented as

           R  =  R_o [1 + \alpha  \Delta T]

Where R_o is the initial resistance

Making the change in temperature the subject of the formula

     \Delta T = \frac{1}{\alpha } [\frac{R}{R_o} - 1 ]

Now from ohm law

           I = \frac{V}{R}

This implies that current varies inversely with current so

           \frac{R}{R_o} = \frac{I_o}{I}

Substituting this we have

       \Delta T  = \frac{1}{\alpha } [\frac{I_o}{I} - 1 ]

From the question we are told that

    I  = \frac{I_o}{8}

Substituting this we have

   \Delta T  = \frac{1}{\alpha } [\frac{I_o}{\frac{I_o}{8} } - 1 ]

=>     \Delta T  = \frac{1}{3.9 * 10^{-3}} (8 -1 )

        \Delta T  = 1795 K

6 0
3 years ago
A spaceship starting from a resting position accelerates at a constant rate of 9.8 m/s. How far will the spaceship travel if its
Dvinal [7]

300 000 0 squared = 2 x 9.8 distance

KINEMATICS

Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.


speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time


v=u+at

v^2=u^2+2as

s=ut+1/2at^2

3 0
3 years ago
The mRNA codon CCU could mutate to?
Gekata [30.6K]


UUA, UUG, CUU, CUC, CUA and CUG
So the code CUU could mutate to CUC, CUA or CUG 
5 0
3 years ago
A âsleeping policemanâ is a bump placed in the road to restrict the speed of cars. What radius of curvature should the bump have
asambeis [7]

To solve this problem, the concepts related to the balance of forces must be applied. In this case the two forces that must be in balance are the Weight and the centripetal force. Both forces are derived from Newton's second law, one of the linear movement and the other of the angular movement. The centripetal force is given by the function

F_c = \frac{mv^2}{R}

Here,

m = mass

v =Velocity

R = Radius

And the force product of the weight is given under the function

F_w =mg

Here,

m = Mass

g = Gravity

As both forces are in balance we will have

\sum F =0

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F_w = F_c

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R = \frac{v^2}{g}

Speed would be

V = 40km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 11.11m/s

Replacing

R = \frac{11.11^2}{9.8}

R = 12.59m

The radius must be 12.6m

5 0
3 years ago
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