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Pie
3 years ago
13

What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

ilograms?
Physics
2 answers:
Lyrx [107]3 years ago
3 0

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

\sf \: F=ma

Where,

  • F is force
  • m is mass
  • a is acceleration

In our case,

  • F = ?
  • m = 2500 kg
  • a = 20m/s

\tt \: F_{net}  = 2500 \times 20 \\   \tt= 50000

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

Inessa [10]3 years ago
3 0

Answer:

Explanation:

f =ma

F 2500 kg (20m/s-0m/s/15s)

F=2500kg(1.33m/s²)

F =3,325 N

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a football is kicked toward a goal keeper with an initial speed of 20m/s at an angle of 45 degrees with the horizontal .at the m
algol [13]

Answer:

3.18 m/s

Explanation:

Given that

Initial speed of the ball, u = 20 m/s

Angle of inclination, θ = 45°

Distance from the ball, h = 50 m

Using equations of projectile to solve this, we have

We start by finding the time of flight, T

T = 2Usinθ/g

T = (2 * 20 * sin45)/9.8

T = (40 * 0.7071) / 9.8

T = 28.284/9.8

T = 2.89 s

Next we find the Range, R

R = u²sin2θ/g

R = (20² * sin 90) / 9.8

R = (400 * 1) / 9.8

R = 400/9.8 = 40.82 m

Distance the gk must cover

40.82 - 50 m

-9.18 m or 9.18 m in the opposite direction.

Speed of the GK = d/t

9.18 / 2.89 = 3.18 m/s

5 0
4 years ago
The purpose of technology is to solve problems and meet needs. True False
BARSIC [14]

The above given sentence is true reason being the use of Technology.

Explanation:

The basic purpose double technology is to make hard work easier and help in meeting the needs. Technology was being developed and is being upgraded so as to make some of the tasks, which were harder to do without it, easier.

Development of Technology has made the work easier and the needs are being met with an additional profit of saving time.

4 0
3 years ago
Two parallel plates that are initially uncharged are separated by 1.7 mm, have only air between them, and each have surface area
yaroslaw [1]

Answer:

5.63\cdot 10^{-6} C

Explanation:

The capacitor of a parallel-plate capacitor is given by:

C=\epsilon_0 \frac{A}{d}

where

A is the area of each plate

d is the separation between the plates

\epsilon_0 is the vacuum permittivity

The energy stored in a capacitor instead is given by

U=\frac{1}{2}\frac{Q^2}{C}

where

Q is the charge stored in each plate

Substituting the expression we found for C inside the last formula,

U=\frac{1}{2}\frac{Q^2 d}{\epsilon_0 A}

And re-arranging it

Q=\sqrt{\frac{2U\epsilon_0 A}{d}}

Now if we substitute

d=1.7 mm=0.0017 m\\A=16 cm^2 = 16\cdot 10^{-4} m^2\\U = 1.9 J

We find the charge stored on the capacitor:

Q=\sqrt{\frac{2(1.9)(8.85\cdot 10^{-12})(16\cdot 10^{-4})}{0.0017}}=5.63\cdot 10^{-6} C

7 0
3 years ago
An Olympic runner complete the 200 m sprint and 23 seconds. What is the runners average speed (round your answer to the nearest
kipiarov [429]
Should be 8.7 m/s. Just divide 200 by 23 and round from there.
3 0
3 years ago
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center. If
zvonat [6]

Answer:

The distance between their eye and the ceiling is 33.06 m.

Explanation:

Given that,

The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm

Diameter of the eye of pupil, d = 5.1 mm

Wavelength, \lambda=550\ nm

We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :

L=\dfrac{Dd}{1.22\lambda}\\\\L=\dfrac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}\\\\L=33.06\ m

So, the distance between their eye and the ceiling is 33.06 m.

3 0
3 years ago
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