Answer:
mass flow rate at water condenses is 36.72 kg/min
Explanation:
given data
temperature t1 = 38°C
temperature t2 = 14°C
humidity ∅= 97 % = 0.97
rate v = 510 m³/min
to find out
mass flow rate at water condenses
solution
by gas equation we find here mass flow rate that is
pv = mRT
put here value and p is 0.066626 bar at 38°C and find m
m = 0.06626 × 
× 510 / 287×311
m = 37.85 kg/min
so at water condenses mass flow rate is express as
∅ = M / m
Mass flow rate M = ∅ × m
M = 0.97 × 37.85
mass flow rate = 36.72 kg/min
so mass flow rate at water condenses is 36.72 kg/min
We are given that the wavelength ʎ is from 400 nm to 700
nm. The formula for this is:
d sin a =m * ʎ
where,
d = slit separation = 1 mm / 750 lines = 1/750
a = angle
m = 1
ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm
Rewriting the formula in terms of angle a:
a = sin^-1 (m ʎ / d)
when ʎ = 0.0004 mm
a = sin^-1 (0.0004 / (1/750))
a = 17.46°
when ʎ = 0.0007 mm
a = sin^-1 (0.0007 / (1/750))
a = 31.67°
Hence the range of angles is from 17.46° to 31.67<span>°.</span>
The answer is C why because I know it is
Answer:
Explanation:
We shall solve this question with the help of Ampere's circuital law.
Ampere's ,law
∫ B dl = μ₀ I , B is magnetic field at distance x from the axis within wire
we shall find magnetic field at distance x . current enclosed in the area of circle of radius x
= I x π x² / π R²
= I x² / R²
B x 2π x = μ₀ x current enclosed
B x 2π x = μ₀ x I x² / R²
B = μ₀ I x / 2π R²
Maximum magnetic B₀ field will be when x = R
B₀ = μ₀I / 2π R
Given
B = B₀ / 3
μ₀ I x / 2π R² = μ₀I / 2π R x 3
x = R / 3
b ) The largest value of magnetic field is on the surface of wire
B₀ = μ₀I / 2π R
At distance x outside , let magnetic field be B
Applying Ampere's circuital law
∫ B dl = μ₀ I
B x 2π x = μ₀ I
B = μ₀ I / 2π x
Given B = B₀ / 3
μ₀ I / 2π x = μ₀I / 2π R x 3
x = 3R .
Answer:
(A) Velocity will be 1.88 m/sec
(b) Force will be 187.45 N
Explanation:
We have given work done = 4780 j
Distance d = 25.5 m
(A) Mass of the truck m = 
We know that kinetic energy is given by
So 
(B) We know that work done is given by
W = Fd
So 
