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Rama09 [41]
3 years ago
7

What is (5x-2)(4x^2 -3x-2)

Mathematics
2 answers:
Ronch [10]3 years ago
8 0
Answer: 20x^3 - 23x^2 - 4x + 4

Explanation:

Use distributive property:

(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4
Novay_Z [31]3 years ago
8 0

Answer:

20x^3-23X^2-4X+4

Step-by-step explanation:

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Hello today is my birthday please help !!
scoray [572]

Answer:

the last one(y=2(2/3)^x) is the correct answer

Step-by-step explanation:

I identify two coordinate on the graph (0,2) and (1,3) and I noticed only the last one gives you a appropriate output if you plug the correspond input value

4 0
2 years ago
Complete the statements and equations to find the product of 6 and 13
Alina [70]

Answer:

78

Step-by-step explanation:

the product of 6 and 13 =78

8 0
3 years ago
Angela was looking at 17 different colors to paint her bedroom. She liked about one fourth of the colors. About how many colors
dusya [7]

Answer:4.25, so about 4 or 5

Step-by-step explanation:

1/4 = x/17

-Cross multiply-

4*x = 1*17

4x = 17

-divide-

17/4 = x

x = 4.25

7 0
3 years ago
Between 0900 and 10 30, a man walks a distance of 27 km. What is his average speed in km/h?
kramer

Answer:

18

Step-by-step explanation:

0900 to1030 is 1.5 h

Take 27/1.5

Then you will get the answer

6 0
2 years ago
Determine what type of model best fits the given situation:
kondaur [170]

Answer:

Ok, i will suppose the situation that:

The rocket has a constant speed S (So the acceleration of the rocket is equal in magnitude, but opposite in direction, to the gravitational acceleration)

Here we can remember that:

Velocity = distance/time.

Then if the distance is the height of the rocket, we can write this as:

H = velocity*time

h = S*t

This is a linear model that represents the height of the rocket as a function of time.

Case 2:

The rocket is fired with an initial velocity v0, but no acceleration:

In this case the only acceleration acting on the rocket is the gravitatonal acceleration pulling the rocket down, so the acceleration is:

a = -g

To get the velocity as a function of time, we should integrate:

a = -g*t + v0

To get the height as a function of time, we integrate again:

h(t) = (-g/2)*t^2 + v0*t + p0

Where p0 is the initial position of te rocket, but the rocket starts at the ground, so p0 = 0m.

The height as a function of time is:

h(t) = (-g/2)*t^2 + v0*t

This is a quadratic equation.

8 0
3 years ago
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