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Romashka [77]
3 years ago
7

2.98 + 5.3 = Decimal Addition please help ​

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

8.28

Step-by-step explanation:

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WORTH 100 POINTS!!!!!
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Answer:

1. This graph is not a function, because for every y there are more than one x.

2. This graph is not linear because it is not a straight line.

3. It took them 6 hours to get to their destination.

4. The destination was 325 miles away.

5. They might have stopped at a restaurant to eat.

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2 years ago
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Given that
BaLLatris [955]

Answer:

x=21/5

Step-by-step explanation:

5x:9 = 7:3

Turn the ratios into fractions:

5x/9 = 7/3

Then cross mutiply

15x=63

x=21/5

8 0
2 years ago
I need help I will rate you brainliest
Tems11 [23]

Answer:

it would be subtraction

Step-by-step explanation:

Because if you are trying to get you would do 2-2 to get 0 and have x by itself

3 0
3 years ago
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Find |−5|.<br> A. −5<br> B. 5<br> C. one-fifth<br> D. –one-fifth<br><br> HELP!!!
Volgvan

recall that when it comes to absolute value expressions, once we remove the bars, it turns always to positive, so | -5 |, the bars go poof, and tada!!   5.

4 0
3 years ago
(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
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