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Romashka [77]
3 years ago
7

2.98 + 5.3 = Decimal Addition please help ​

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

8.28

Step-by-step explanation:

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Paul's plumbing : 90 + 40h
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Answer for brainliest!!! :> Three hens can lay 3 eggs in 3 days. How many hens would lay 3 eggs in 9 days?
marta [7]

It would still be the same 3 hens in 9 days.

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2 years ago
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Anyone know how to do this
svlad2 [7]

Answer:

The area of the rectangle on the left side is

9cm \:  \times 4cm = 36 {cm}^{2}

The area of the bottom rectangle is

6cm \times 2cm = 12 {cm}^{2}

The total area of the composite figure will be

36 {cm}^{2}  + 12 {cm}^{2}  = 48 {cm}^{2}

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0
3 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

7 0
3 years ago
Helppppp plzzzz ASAP!!!!!!<br> Thank you!!!!!!
Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values ​​of p from s

PS = (4 - 2  , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4  ,  6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values ​​of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

16

3 0
3 years ago
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