I believe the answer is B
Missing information :
The model was omitted from the question ; the possible model relating to the question was browsed online and could possibly be :
N(t) = 1.07t^2.3 for 0 ≤ t ≤ 10 months
Answer:
30.9 cases per month
Step-by-step explanation:
Given the model to determine the number of rats that have developed cancer after initial exposure ; N(t) = 1.07t^2.3
N(t) = 1.07t^2.3
Take the first derivative of N with respect to t to obtain the rate of change ;
N'(t) = (1.07)(2.3)t^2.3-1
N'(t) = (1.07)(2.3)t^1.3
The rate of growth of cancer cases at the 7th month can be calculated thus :
t = 7
N'(7) = (1.07)(2.3)t^1.3
N'(7) = 1.07 * 2.3 * 7^1.3
N'(7) = 1.07 * 2.3 * 12.549529
N'(7) = 30.884
The rate of growth of cancer at the 7th month is 30.9 cases per month.
120 + 5k = 350
120 + 5k - 120 = 350 - 120
5k = 230
5k/5 = 230/5
K = 46
Answer:
6x^8 y^5
Step-by-step explanation:
