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Katen [24]
3 years ago
14

Solve the above attached questionThanks​

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

23

Step-by-step explanation:

Given,

tan²A - 5tanA + 1 = 0

tan²A - 5tanA = -1

tanA(tanA - 5) = -1

tanA - 5 = -1/tanA

We know that 1/tanA= cotA

So,

tanA - 5 = -cotA

tanA + cotA= 5

Now, Making square of both sides,

(tanA +cotA)² = 5²

Expanding RHS by (a + b)² = a² + b² +2ab tan²A + cot²A + 2tanA.cotA= 25

tan²A + cot²A + 2tanA ×(1/tanA) = 25

tan²A + cot²A + 2 = 25

tan²A + cot²A = 25-2

tan²A + cot²A = 23

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8 0
3 years ago
Can y’all help me on question 5?!
iris [78.8K]

Answer:

Answer is B:(-4,0)

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3 years ago
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Goryan [66]
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3 years ago
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Answer:

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The two points the equation should go through are (-2,9) and (2,-9), (Dark Green and Light Blue).

The slope-intercept is calculated using the two points above;

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Slope = -18/4 or -9/2

Hope this helps!

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3 years ago
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