Question

Solve the above attached questionThanks​

Answer 1

Answer:

23

Step-by-step explanation:

Given,

tan²A - 5tanA + 1 = 0

tan²A - 5tanA = -1

tanA(tanA - 5) = -1

tanA - 5 = -1/tanA

We know that 1/tanA= cotA

So,

tanA - 5 = -cotA

tanA + cotA= 5

Now, Making square of both sides,

(tanA +cotA)² = 5²

Expanding RHS by (a + b)² = a² + b² +2ab tan²A + cot²A + 2tanA.cotA= 25

tan²A + cot²A + 2tanA ×(1/tanA) = 25

tan²A + cot²A + 2 = 25

tan²A + cot²A = 25-2

tan²A + cot²A = 23