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3 years ago

A line includes the points (8,-2) and (-8,-4). What is the slope intercept

Mathematics

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

The equation of the line would be y = 1/8x - 3

Step-by-step explanation:

to find the slope intercept form of the line, you must first find the slope. You can do this using the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-2 - -4)/(8 - -8)

m = 2/16

m = 1/8

Then you can use this slope along with either point in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y + 4 = 1/8(x + 8)

y + 4 = 1/8x + 1

y = 1/8x - 3

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(a) Use Euler's method with step size 0.2 to estimate y(1.4), where y(x) is the solution of the initial-value problem y' = 4x −

Verizon [17]

Answer:

$y\left(1.4\right)=0.992$ .

Step-by-step explanation:

The Euler's method states that $y_{n+1}=y_n+h \cdot f \left(x_n, y_n \right)$ , where $x_{n+1}=x_n + h$ .

To find $y\left(1.4 \right)$ for $y'=- 4 x y + 4 x$ when $y\left(1 \right)=0$ , with step size $h=0.2$ using the Euler's method you must:

We have that $h=0.2=\frac{1}{5}$ , $x_0=1$ , $y_0=0$ , $f(x,y)=- 4 x y + 4 x$ .

Step 1.

$x_{1}=x_{0}+h=1+\frac{1}{5}=\frac{6}{5}$

$y\left(x_{1}\right)=y\left( \frac{6}{5} \right)=y_{1}=y_{0}+h \cdot f \left(x_{0}, y_{0} \right)=0+h \cdot f \left(1, 0 \right)=0 + \frac{1}{5} \cdot \left(4.0 \right)=0.8$

Step 2.

$x_{2}=x_{1}+h=\frac{6}{5}+\frac{1}{5}=\frac{7}{5}=1.4$

$y\left(x_{2}\right)=y\left( \frac{7}{5} \right)=y_{2}=y_{1}+h \cdot f \left(x_{1}, y_{1} \right)=0.8+h \cdot f \left(\frac{6}{5}, 0.8 \right)=0.8 + \frac{1}{5} \cdot \left(0.96 \right)=0.992$

The answer is $y\left(1.4\right)=0.992$

3 0

3 years ago

What is the unknown angle measure in the triangle?

Black_prince [1.1K]

180 degrees in a triangle therefore you will subtract 54 and 79 from 180 which then gives you the answer --47--
do you understand how to do it now ?

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3 years ago

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I am Lyosha [343]

Answer:

Not a function

Step-by-step explanation:

there's two 9's

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3 years ago

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If a varies jointly as b and c,

Alborosie

Given:

a varies jointly as b and c.

a=6 when b=2 and a=3.

To find:

The variation constant and the equation of variation.

Solution:

a varies jointly as b and c.

$a\propto bc$

$a=kbc$ ...(i)

Where, k is the constant of proportionality.

a=6 when b=2 and a=3.

$6=k(2)(3)$

$6=6k$

$\dfrac{6}{6}=k$

$1=k$

The value of k is 1.

Putting k=1 in (i), we get

$w=1xy$

$w=xy$

Therefore, the variation constant is 1 and the equation of variation is $w=xy$ .

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2 years ago

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3. coordinate plane showing the point 2, 10

Katena32 [7]

Answer:

geometric sequence with initial value 20 and common ratio 1/2
average rate of change on [1, 3] = -7.5

Step-by-step explanation:

(a) The given points have sequential values of x and values of y that are each 1/2 the value before. The common ratio tells us the sequence is a geometric sequence.

(b) The first given point is (2, 10), so extrapolating backward, we determine the previous point to be ...

... (2-1, 10/(1/2)) = (1, 20)

Thus, we have enough information to determine the average slope between n=1 and n=3.

... (difference in y)/(difference in n) = (5 -20)/(3 -1) = -15/2 = -7.5

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3 years ago