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Westkost [7]
3 years ago
10

Please- why does my lesson have no information on what's in my assignment. anyways, please help :')

Chemistry
1 answer:
taurus [48]3 years ago
4 0

Answer:

the answer is 55 cg/L

Explanation:

Knowing the conversions, there is 100 cg in one g. if there is .55 g/mL then you multiply by a 100 to get 55 cg/L.

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4 years ago
Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions
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5 0
3 years ago
Scientific notation of (4.5+ 17) x 104 -1.5 x 104
Naddik [55]

Answer:

4.5× 104 + 1.7× 105. Firstly, we need to ensure that both exponents have the same value. Thus, we need to change the value of 1.7 x 105 to 17 x 104. If both already had the same exponential value, you can neglect this step. 4.5× 104+ 17 × 104. Now, we will take exponentials common and add the decimal values. (4.5+ 17) × 104 | 21.5 × 104. Similar steps are taken for the subtraction phase we just need to retrace our steps and find differences rather than sums. These lessons and worksheets show you how to perform sums and differences with values that are in scientific notation.

Explanation:

I think it helps you

6 0
3 years ago
Which of the following is NOT one of the three main global climate zones?
krok68 [10]
The answer is Latitude (B)
8 0
3 years ago
Calculate the values of ΔU, ΔH, and ΔS for the following process:
kykrilka [37]

The values of the changes are

ΔH = 46.44kJ

Δu =  43.34Kj

ΔS = 126.6 J/K

<h3>How to find change in H</h3>

= 1 mol + 75.3 (100 + 273) - 25 + 273 + 1 * 40.79

= 5.6475 + 40.79

= 46.44kJ

<h3>How to find change in S</h3>

1 mol + 75.3 x ln 373/298 + 1 mol x 40.79

= 0.1263

ΔS = 126.6 J/K

<h3>How to find the change in U</h3>

46.44 - 0.00831 * 373

= 43.34Kj

Read more on molar heat here:

brainly.com/question/13439286

#SPJ1

5 0
2 years ago
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