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Kipish [7]
2 years ago
11

How many atoms are in 4.5 g of AICI3?

Chemistry
1 answer:
HACTEHA [7]2 years ago
8 0

Answer:

2.047 × 10^22 atoms.

Explanation:

To calculate the number of atoms (nA) in AlCl3, we first need to find the number of moles in the compound, AlCl3.

Molar mass of AlCl3 = 27 + 35.5(3)

= 27 + 106.5

= 133.5g/mol

Using mole = mass/molar mass

mole = 4.5/133.5

mole = 0.034moles

number of atoms in a substance (nA) = number of moles (n) × Avagadros number or constant (6.02 × 10^23 atoms)

nA of AlCl3 = 0.034 × 6.02 × 10^23

nA = 0.2047 × 10^23

nA = 2.047 × 10^22 atoms.

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scoundrel [369]

Answer: 1) only a salt and water

An acid and base reacts together to undergo neutralization to form salt and water.

HCl+NaOH\rightarrow NaCl+H_2O

where HCl is an acid and NaOH is a base to form salt (NaCl) and water (H_2O).

Answer: 2) The formula of the hydrogen ion is often written as H^+.

All acids dissociate in water to give  H^+ ions.

Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.

HCl\rightarrow H^++Cl^-

Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.

NaOH\rightarrow Na^++OH^-

Answer: 4) A conjugate acid base pair  transfers hydrogen ion.

CH_3COO^-+H_2O\rightarrow CH_3COOH+H_3O^+

Here CH_3COO^- accepts a proton and thus act as a base and the corresponding CH_3COOH is its conjugate acid.

Answer: 5) Bronsted Lowry acid is a substance that donates protons.  Bronsted Lowry base is a substance that accepts protons.

NH_4^+ and NH_3

NH_3+H^+\rightarrow NH_4^+

NH_3 is a acid which accepts proton and thus acts as base to form conjugate acid NH_4^+.


4 0
2 years ago
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PLEASE HELP<br> Thanks to Einstein's equation E = mc² we now know that energy is equivalent to what?
Nitella [24]
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at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were
Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1

Putting values in above equation, we get:

\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L

Percent change of volume = \frac{\text{Change in volume}}{\text{Initial volume}}\times 100

Percent change of volume = \frac{(2-1.5)}{2}\times 100=25\%

Hence, the percent change in volume will be 25 %

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Can anybody help please
romanna [79]

Answer:

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