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2 years ago

Peaches are 8 for $2. Jill bought 12 peaches. How much did she spend?

Mathematics

1 answer:

Marianna [84]2 years ago

7 0

Answer:

$ 3

Step-by-step explanation:

8 peaches= $2

4 peaches= $ 1

although I'm not quite sure

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Write this in slope intercept form (-3,-1) , (4,-1) Thanks in advance!

bearhunter [10]

Y= -1 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

The minute hand of a clock is 7 inches long. How far does the tip of the minute hand move in 5 minutes? If necessary, round the

FromTheMoon [43]

The movement of the minute hand is circular.

Tangence speed is V=2Rπ/T= 2*7*3.14/3600 inches/sec=0.012211 inches/sec

The path (distance) that minute hand past is D=V*t = 0.012211 * 5 min= 0.012211 * 300sec=>

D=3.663≈3.66 inches

Good luck!!!

6 0

3 years ago

A train travels train travels 288 kilometre at a uniform speed. If the speed had been 4 kilometre per hour more it would have ta

kiruha [24]

Answer:

Let the speed of the train be x km/h.

Case 1:

Distance = 288 km

Speed = x km/h

Time = Distance/Speed

= 288/x h

Case 2:

Distance = 288 km

Speed = (x+4) km/h

Time = 288/x + 4 h

Since 288/x > 288/x + 4

288/x - 288/x+4 = 1

288[1/x - 1/x+4 ] = 1

[ x + 4 - x / x(x + 4) ] = 1/288

[4 / x^2 + 4x ] = 1/288

x^2 + 4x = 1152

x^2 + 4x - 1152 = 0

x^2 + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0 , x - 32 = 0

x = -36 , x = 32

x = -36 , rejected since speed cannot be negative.

Therefore , speed of the train = 32 km/h

4 0

3 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation: