X= 1 number
Y= a number that is 1 less than x
Y= x-1
The sum of squares=
X^2 + (x-1)^2 = x^2 + x^2 - 2x + 1
X^2 + x^2 - 2x + 1 = 2x^2 - 2x + 1
Assuming that integers = numbers. We could try some values
When x = 0, the sum of squares = 1
When x = -1, the sum of squares = 4
When x = 1, the sum of squares = 1
If you put this into a graph, it is a parabola and we see that the minimum value hits at x = 1/2.
To check this value:
2x^2 - 2x + 1 = 2·(1/4) - 2·(1/2) + 1
2·(1/4) - 2·(1/2) + 1 = 1/2 - 1 + 1
1/2 - 1 + 1 = 1/2
When you look back at the question, it asks for 2 answers
X= 1/2
X-1 = -1/2
What is the sum of their squares?
1/4 + 1/4 = 1/2
That fits with graph too.
Answers: 1/2 and -1/2
Hope this helps!!
I belive the answer is x=N+6
Answer:
<h2>
<em>x</em><em>=</em><em>8</em></h2>
<em>Solu</em><em>tion</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
From what you have shared I see y = sqrt(x). I do not see "b."
Did you perhaps mean y = -2sqrt(x)? In that case, the graph of y=sqrt(x) would be reflected in the x-axis and the resulting graph stretched by a factor of 2.
D. three hundred nine thousand, seventy
