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konstantin123 [22]
3 years ago
8

3.please help me out

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

Step-by-step explanation:

5×5²

=5×5×5

=125

index form= 5³

weqwewe [10]3 years ago
5 0

Answer:

125

Step-by-step explanation:

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The following three shapes are based only on squares, semicircles, and quarter circles. Find the perimeter and the area of each
MakcuM [25]
The perimeter = 4 * length of a semicircle of radius 5 == 4*  pi * 5 =  20 pi cm



The area of one of the clear parts = 1/2 area of square - area semicircle

= 1/2 * 10^2  -  1/2 pi *5^2 = 50 - 12.5pi 

So area of shaded parts =  area of square -  4 (50 - 12.5pi)
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4 years ago
Determine the product. 800.5 x (2x10^6)
zhenek [66]
D. 10^6 = 1000000 x 2 = 2000000 x 800.5 = 1601000000 = 1.601 x 10^9
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3 years ago
Which of the following could be the graph of 3x + 4y = 12?​
Elan Coil [88]

Answer:

A graph that goes through (4, 0), (8, -3), (0, 3), and (-4, 6)

Step-by-step explanation:

Hello!

To find what this looks like it is easier to put it into slope-intercept form which is y = mx + b

To get our equation to look like that we have to get y by itself

3x + 4y = 12

Subtract 3x from both sides

4y = -3x + 12

Divide both sides by 4

y =- \frac{3}{4}x  + 3

We now know the y-intercept is (0, 3)

Now we follow the slope to give us more points

More points are (4, 0), (8, -3), and (-4, 6)

The answer would be a graph that goes through those points.

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6 0
3 years ago
A fossilized leaf contains 18% of its normal amount of carbon 14. How old is the fossil (to the nearest year)? Use 5600 years as
Sati [7]

Answer: The age of the fossilized leaf is 13829 years.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

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a) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

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b) for finding the age

t=\frac{2.303}{0.00012}\log\frac{100}{18}  

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The age of the fossilized leaf is 13829 years.

7 0
3 years ago
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