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3 years ago

Solve the equation : above

Mathematics

2 answers:

Lana71 [14]3 years ago

8 0

Answer:

5/8 =0.625

Step-by-step explanation:

Hope this helps

jek_recluse [69]3 years ago

4 0

5/8 is equal to 0.625 :) hope this helps

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Which equations represent functions?

never [62]

Answer:

2x + 3y = 10, 3y = 18 (in both cases, for each input x, there is exactly one output y.

Step-by-step explanation:

3y = 10 - 2x, or y = (1/3)(10 - 2x) Yes, this is a function.

4x = 16 → x = 4 NOT a Function, because for x = 4 there are an infinite number of possible y -values

2x - 3 = 14 → 2x = 17 → x = 17/2 Not a function. See reason given above.

3y = 18 → y = 6 Function

2x = 14.6 → x = 7.3 Not a function. See reason given above

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4 years ago

Please help pre Algebra question

qaws [65]

Answer:

4=No

-3=No

2=Yes

0=No

Step-by-step explanation:

enter enter all the factors into the equation and see which one equals -28 on both sides at the end.

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3 years ago

Find the distance across the lake. Assume the triangles are similar.

irina1246 [14]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

N+ 12 = -24<br><br> Help please

omeli [17]

Answer:

n = -36

Step-by-step explanation:

The answer is -36 because:

1) We first have to subtract -24 and 12 to find n

-24 - 12 = -36

This is because whenever there are two negative signs, multiply it.

Negative x Negative = Positive

We have to do, 24 + 12 which is 36. Finally, we just put the greater number's sign to the answer. 24 is greater than 12, therefore, we put a negative sign before 36.

Hope this helps!

7 0

3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

3 years ago