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yarga [219]
3 years ago
15

P=q+7+s. Solve for s

Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer:

s = P-q-7

Step-by-step explanation:

P=q+7+s   (subtract q) from both sides

P-q = 7 + s   (subtract 7 from both sides)

P-q-7 = s   (rearrange)

s = P-q-7

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Line segment XY is tangent to circle Z at point U. If the measure of UV is 84, what is the measure of YUV. A. 42 B. 84 C. 96 D.
MissTica

Answer is 42. Don't listen to the guy that said it's 168. I did the test and it marked it wrong.

4 0
3 years ago
Read 2 more answers
I need help with this right away. Please.
Nostrana [21]
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  2. ∠1 ≅ ∠3 . . . . vertical angles are congruent
  3. ∠2 ≅ ∠3 . . . . transitive property of congruence; both are ≅ ∠1 . . . (angle of ASA)
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3 0
4 years ago
Given the functions f(x) = left parenthesis 2 x right parenthesis squared plus  x  minus 1 
klio [65]
I'm going to rewrite f(x) and g(x) so that I don't get confused. 

Based on your description: 

f(x) = (2x)^{2} + x - 1 simplified to 4x^{2} + x - 1

g(x) = x^{2} + 3x - 3

Now we handle parts A-D.

A. f(x) + g(x)

We combine like terms. 

4x^{2} + 5x^{2} + x + 3x - 1 - 3 = 5x^{2} + 4x - 4

B. f(x) - g(x)

Again combine like terms like normal except this time subtracting. 

4x^{2} - x^{2} + x - 3x - 1 - (- 3) = 3x^{2} - 2x + 2

C. 2f(x) + 2g(x)

Multiply, then again CLT

2f(x) = 8x^{2} + 2x - 2
2g(x) = 2x^{2} + 6x - 6

Combine like terms to get 10x^{2} + 8x - 8

D. 2f(x) - 2g(x) 

Use the same 2f(x) and 2g(x) terms and this time just subtract.

You get 6x^{2} - 4x + 4


6 0
4 years ago
How do you solve these?
Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 =  <u>2*2*2 </u><u>*2</u><u> </u>* 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = -  <u>3 * 3 * </u><u>3</u> * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0
3 years ago
5x+10=25 Step 1: 5x=155x=15 Step 2: x=3x=3 Step 3: 5\left(3\right)+10=255(3)+10=25 Step 4: 15+10=2515+10=25 Step 5: 25=2525=25 P
marishachu [46]

Step-by-step explanation:

We need to solve 5x+10=25 ....(1)

Step 1.

Subtract 10 to both sides of the above equation.

5x+10-10=25-10

5x=15

Step 2,

Divide each side by 5.

\dfrac{5x}{5}=\dfrac{15}{5}\\\\x=3

If we want to check whether it is correct or not, step are as follows :

Put x = 3 in equation (1)

5(3)+10=15+10

=25

It means that the above steps are correct.

8 0
3 years ago
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