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AveGali [126]
3 years ago
13

Give g(x)=2x+3, find g(-3)

Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

2

Step-by-step explanation:

g(x)=2x+3

La derivada de un polinomio es la suma de las derivadas de sus términos. La derivada de cualquier término constante es 0. La derivada de ax  

n

 es nax  

n−1

.

2x  

1−1

 

Resta 1 de 1.

2x  

0

 

Para cualquier término t excepto 0, t  

0

=1.

2×1

Para cualquier término t, t×1=t y 1t=t.

2

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Plzz help me to find coefficient in binomial theorem (25 points)
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<em>Denote x2 by y. </em>

<em>  </em>

<em>(x2-3)7=(y-3)7 </em>

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<em>This is a binomial expansion in y, and you want the coefficient of y4 because y4=x8 </em>

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<em>You have 7 terms of (y-3) in (y-3)7.  To get the fourth power of y, you need to choose y from four of the terms.  The number of ways you can do this is the combinations of 7 things taken 4 at a time.  This is: </em>

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5 0
3 years ago
Ok so this isn't actual homework but I need help calculating this.
jeka57 [31]
Ok so there is 60 minutes in an hour and you have 107 minutes so
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What is 31 in tens and ones
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5 0
3 years ago
1. What is the slope of a line that is parallel to the line represented by the equation y=-2/5x + 4/5
lbvjy [14]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .  . . . . . . . . .

We are asked to find the slope of the line that is parallel to the line \star~\mathrm{y=-\cfrac{2}{5}x+\cfrac{4}{5}}.

\triangle~\fbox{\bf{KEY:}}

  • Parallel lines have the same slope.

So let's first determine the slope of the first line, and then let's find the slope of the line that's parallel to it.

\circ\!\!\!\star\mathcal{HINT:}

  • The slope is the coefficient of x.

So the slope is

\star~\mathrm{-\cfrac{2}{5}}.

Can you guess the slope of the line that is parallel to the first line?

That's right! The slope is...

\star~\mathrm{-\cfrac{2}{5}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0
2 years ago
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