Answer:
45,000 is the starting salary with zero sales
.05 is the amount multiplied by the number of sales that is added to her salary
For each sale we add .05 to her salary
Step-by-step explanation:
y = 45,000 +.05x
Rewriting as
y = .05x +45,000
This is in slope intercept form ( y=mx+b) where m is the slope and b is the y intercept
.05 is the slope and 45,000 is the y intercept
45,000 is the starting salary with zero sales
.05 is the amount multiplied by the number of sales that is added to her salary
For each sale we add .05 to her salary
Answer:
i think it is 234 i am not sure
Step-by-step explanation:
Answer:
<u>Equation</u>: 
<u>The balance after 5 years is: $1742.43</u>
<u></u>
Step-by-step explanation:
This is a compound growth problem . THe formula is:

Where
F is future amount
P is present amount
r is rate of interest, annually
n is the number of compounding per year
t is the time in years
Given:
P = 1500
r = 0.03
n = 12 (compounded monthly means 12 times a year)
The compound interest formula modelled by the variables is:

Now, we want balance after 5 years, so t = 5, substituting, we get:

<u>The balance after 5 years is: $1742.43</u>
59.9%
Sorry I don’t have time to explain in the middle of an exam