The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
(0,0) (2,4) (-2,-4)
Step-by-step explanation:
Answer:
Step-by-step explanation:
5x + 9y = -11
3x + 9y = -3
5x + 9y = -11
-3x - 9y = 3
2x = -8
x = -4
-12 + 9y = -3
9y = 9
y = 1
(-4, 1)
Answer is C
Answer:
incorrect is They have a sum of -14
Answer:
I'm not entirely sure what the question is but every thing under 12.5 is closer to 12, everything 12.5 and upwards like 12.87 would be closer to 13
