I Think the awnser would be 9,jsdfgeuriyftveywoqtfryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
Answer:
4
step by step:
b-9=4
We can use the Pythagorean theorem to solve for the perimeter of the kite.
a² + b² = c²
3² + 4² = UV²
9 + 16 = UV²
25 = UV²
√25 = √UV²
5 = UV
In the kite, adjacent sides are the same so UV = VW
3² + 9² = UX²
9 + 81 = UX²
90 = UX²
√90 = √UX²
9.49 ≈ UX or 3√10 ≈ UX
Now, add to find the perimeter.
5 + 5 + 9.49 + 9.49 or 5 + 5 + 3√10 + 3√10
28.98 or 10 + 6√10
Therefore, the perimeter is approximately 28.98 or 10 + 6√10
Best of Luck!
First triangle side lengths: 9, 4, 8
First triangle perimeter: 21
Second triangle side lengths: 18, 8, 16
Second triangle perimeter: 42
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