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3 years ago

What is the original backward and forward movement of particles in a solid

1 answer:

4 0

<span>A vibration </span><span>is the original backward and forward movement of particles in a solid.</span>

- - Final answer: Vibration

You might be interested in

How much current would flow in a device powered by four 1.5 V batteries through a bulb that had a resistance of 51.0 ohms?

Serhud [2]

Answer:

0.12A

Explanation:

Total voltage produced by the batteries;

V = 1.5 × 4 = 6 v

Then the current that is flowing through the device

Current(I) = V/R

; I = 6/51

;Current = 0.12A

4 0

3 years ago

The moon has a weaker gravitational force than earth. Sofia weighs 50 lbs. on earth. How much will she weigh on the moon? exactl

Neporo4naja [7]

She would weigh less than 50 pounds. everything is super light on the moon. remember that.

3 0

3 years ago

Read 2 more answers

A parallel circuit has three branches. Each branch has a resistance of 37.5 ohms. The total current is 7.5 amps. What is the cur

Sophie [7]

Answer:

Current in each branch will be 2.5 A

Explanation:

We have given that a circuit has three branch each has a resistance of 37.5 ohm

We have also given that a total current of 7.5 A is flows through the circuit

As we know that in parallel circuit total current is the sum of current flowing through each branch

As the resistances of each branch is same so current will also be same

As there is 3 branches in circuit so current in each branch will be $\frac{7.5}{3}=2.5A$

4 0

4 years ago

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.10 m/s

yarga [219]

Answer:

$I=336.6kgm/s$

Explanation:

The equation for the linear impulse is as follows:

$I=F\Delta t$

where $I$ is impulse, $F$ is the force, and $\Delta t$ is the change in time.

The force, according to Newton's second law:

$F=ma$

and since $a=\frac{v_{f}-v_{i}}{\Delta t}$

the force will be:

$F=m(\frac{v_{f}-v_{i}}{\Delta t})$

replacing in the equation for impulse:

$I=m(\frac{v_{f}-v_{i}}{\Delta t})(\Delta t)$

we see that $\Delta t$ is canceled, so

$I=m(v_{f}-v_{i})$

And according to the problem $v_{i}=0m/s$ , $v_{f}=5.10m/s$ and the mass of the passenger is $m=66kg$ . Thus:

$I=(66kg)(5.10m/s-0m/s)$

$I=(66kg)(5.10m/s)$

$I=336.6kgm/s$

the magnitude of the linear impulse experienced the passenger is $336.6kgm/s$

6 0

3 years ago

After World War II the U.S. Air Force carried out experiments on the amount of acceleration a human can survive. These experimen

adell [148]

Answer:

11.9051g

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.8 m/s²

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\frac{70-140}{0.6}\\\Rightarrow a=-116.67\ m/s^2$

Absolute value of the (negative) average acceleration is 116.67 m/s²

$\dfrac{a}{g}=\dfrac{116.67}{9.8}\\\Rightarrow a=11.9051g$

The deceleration was 11.9051g

8 0

4 years ago