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denpristay [2]
3 years ago
8

How much current would flow in a device powered by four 1.5 V batteries through a bulb that had a resistance of 51.0 ohms?

Physics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

0.12A

Explanation:

Total voltage produced by the batteries;

V = 1.5 × 4 = 6 v

Then the current that is flowing through the device

Current(I) = V/R

; I = 6/51

;Current = 0.12A

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Superman is off to visit Lois lane. He sees he's late and increases his flying speed. I know he defies the laws of physics anywa
mario62 [17]

Answer:

975 m/s^2

Explanation:

The formula for rate of acceleration is

(Final velocity - intial velocity)/ time taken

If you plug in your data you will get 975 m/s^2

(1600 m/s -1210 m/s )/.4 s = 975 m^2

7 0
3 years ago
Light is not a wave because it does not need a medium
Reil [10]
It's a tough question as to whether light is a wave or a particle..

The statement is FALSE. Not all types of waves need a medium to propagate. Light can travel without a medium. 

Extra Information:
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7 0
4 years ago
Read 2 more answers
2. A 200.0-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and th
Neporo4naja [7]

Answer: 1960 N

Explanation:

The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:

F_{net}=ma=0

There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:

F_{net}=W-F_f=0

From the previous equation, we find that the frictional force is equal to the weight of the bear:

F_f=W=mg=(200.0 kg)(9.8 m/s^2)=1960 N


8 0
3 years ago
How do electromagnetic forces work?
zlopas [31]
It attracts two charged particles which are separated by a definitive distance.......
4 0
4 years ago
he magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius
RideAnS [48]

Answer:

B = 4.323 T

Explanation:

We are given;

Inner radius; r_i = 0.7 m

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Current; I = 17 KA = 17000 A

Formula for the magnetic field inside the toroid along the inner radius is given by;

B = (μ_o × N × I)/(2πr)

μ_o is vacuum of permeability with a constant value of 4π × 10^(-7) H/m

Plugging in the relevant values, we have;

B = (4π × 10^(-7) × 890 × 17000)/(2 × π × 0.7)

B = (2 × 10^(-7) × 890 × 17000)/(0.7)

B = 4.323 T

4 0
3 years ago
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