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3 years ago

9

The moon has a weaker gravitational force than earth. Sofia weighs 50 lbs. on earth. How much will she weigh on the moon? exactl

y 50 lbs. less then 50 lbs. more than 50 lbs.

2 answers:

d1i1m1o1n [39]3 years ago

8 0

She would weigh less than 50lbs but her mass will not change no matter what planet she is on

Neporo4naja [7]3 years ago

3 0

She would weigh less than 50 pounds. everything is super light on the moon. remember that.

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Can someone explain how exactly to calculate the net force? Do you subtract the smaller number from the larger number? Any help

aleksley [76]

Explanation:

Let's say right is positive and left is negative.

F₁ = -150 N

F₂ = 220 N

Fnet = F₁ + F₂

Fnet = -150 N + 220 N

Fnet = 70 N

The magnitude of Fnet is 70 N, and since it's positive, the direction is to the right.

And since Fnet isn't 0, the force is unbalanced and the motion is changing.

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2 years ago

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

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where

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3 years ago

A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall

dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

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(a) The work done by the force P on the box is given by the following formula:

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x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

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$W_f=F_fx=\mu N x=\mu Mg x$

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J$

(c) The Normal force is

$N=Mg=(46.0kg)(9,8m/s^2)=450.8N$

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

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$W_g=0J$

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Responding variable

Explanation:

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