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2 years ago

Hello plz solve this question whoever solves best gets brainlest and points any links will be reported thank you

Mathematics

2 answers:

Drupady [299]2 years ago

4 0

Answer:

D is correct

Step-by-step explanation:

sdas [7]2 years ago

3 0

Answer:

Step-by-step explanation:

The y axis represents the distance Gil is from home so if the y axis increases this means he is moving farther away from his home. The x axis represents the time which is always moving forward.

The time between 21 and 30 minutes clearly has the y axis increasing so the Gil's distance from home is indeed increasing.

Sidenote: Anime girls are cute don't u agree?

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If there are 9 shirts and 8 pants, how many possible outfits

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Uhh Like 50 different outfits using the same paints and shirts just put differently

Step-by-step explanation:

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2 years ago

Question 6 Express this decimal as a fraction. ? 1.21 = ^ it has a line over the 21.

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2 years ago

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Don Fenley bought a motorcycle that cost $1,250. He paid $250 down and the remainder in 18 monthly payments of $60 each. How muc

topjm [15]

Answer:

Step-by-step explanation:

60x18= 1080-1000 = 80

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3 years ago

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Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E

Lina20 [59]

We have the sum of cubes identity

$a^3 + b^3 = (a + b) (a^2 - ab + b^2)$

and observing that 1 + 4 = 2 + 3, we have

$1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13$

and

$2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7$

Then

$\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}$

Alternatively, we have the well-known sum of cubes formula

$\displaystyle \sum_{i=1}^n i^3 = \frac{n^2(n+1)^2}4$

The sum under the square root is this sum with $n=5$ . Then

$1^3+2^3+3^3+4^3+5^3 = \dfrac{5^2\times6^2}4 = 225 = 15^2$

and so the square root again reduces to 15.

5 0

1 year ago

Find the inverse laplace F(s)=11s/ s^2-12s+52

lions [1.4K]

Answer:

$11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t$

Step-by-step explanation:

We can write $\frac{11s}{s^2-12s+52}$ as follows:

$\frac{11s}{s^2-12s+52}\\=11\left [ \frac{s}{s^2-12s+52} \right ]\\=11\left [ \frac{s}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6+6}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16}$

To find:

$L^{-1}\left [ \frac{11s}{s^2-12s+52 \right ]}\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]$

We will use formulae:

$L^{-1}\left \{ \frac{s-a}{(s-a)^2+b^2} \right \}=e^{at}\cos bt\\L^{-1}\left \{ \frac{b}{(s-a)^2+b^2} \right \}=e^{at}\sin bt$

we get solution as :

$L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+4^2} \right ]+\frac{66}{4}\left [ \frac{4}{(s-6)^2+4^2} \right ] \right ]\\=11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t$

5 0

2 years ago