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aleksandr82 [10.1K]
3 years ago
10

A ball of mass is released from rest at a height of 30 how fast is it going when it hits the ground

Physics
1 answer:
elena55 [62]3 years ago
7 0

Answer:

If the height is in metres, the speed is 24.25m/s

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A(n) ___ object is not electrically neutral.
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Answer:

No, there are always protons, neutrons, and electrons. When an object is neutral, it means the positive and negative charges sum to zero (are equal and opposite). NO, if an object has no net charge it simply means that the amount of positive and negative charges (protons and neutrons) are the same.

Explanation:

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Uno de los miembros de la familia tiene un grupo sanguíneo que no puede explicarse sobre la base de la herencia de este carácter
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A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th
Vesna [10]

Answer:

Average speed of car will be 48 km/hr  

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance t_1=\frac{d}{40}hr

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance t_2=\frac{d}{60}hr

So total time to cover 2d distance t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}

Average speed is the ratio of total distance to total time

So average speed =\frac{2d}{\frac{5d}{120}}=48km/hr

So average speed of car will be 48 km/hr

4 0
3 years ago
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2 sin2(t), y = 2 cos2(
Tanya [424]

The distance traveled by the particle at the given time interval is 0.28 m.

<h3>Position of the particle at time, t = 0</h3>

The position of the particle at the given time is calculated as follows;

x = 2 sin2(t)

y = 2 cos2(t)

x(0) = 2 sin2(0) = 0

y(0) = 2 cos2(0) = 2(1) = 2

<h3>Position of the particle at time, t = 4</h3>

x = 2 sin2(t)

y = 2 cos2(t)

x(4) = 2 sin2(4) = 0.28

y(4) = 2 cos2(4) = 2(1) = 1.98

<h3>Distance traveled by the particle at the given time interval</h3>

d = √[(x₄ - x₀)² + (y₄ - y₀)²]

d =  √[(0.28 - 0)² + (1.98 - 2)²]

d = 0.28 m

Thus, the distance traveled by the particle at the given time interval is 0.28 m.

Learn more about distance here: brainly.com/question/23848540

#SPJ1

7 0
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