What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s

At what distance from the wire is the magnitude of the electric field equal to 2.41 n/cn/c ?

Sladkaya [172]

The correct answer is 1.07m.

The area surrounding an electric charge where its impact may be felt is known as the electric field. When another charge enters the field, the presence of an electric field may be felt. The electric field will either attract or repel the charge depending on its makeup. Any electric charge has a property known as the electric field. The charge and electrical force working in the field determine the strength or intensity of the electric field.

Here, is the charge per unit length, r is the distance from the wire, and

is the free space permittivity ε_0. Electric field due to the long straight wire is,

E= λ/2πε_0r

Rearrange the equation for r.

r=λ/2πε_0E

Substitute 2.41 N/C for E,

E=1.44×10^-10C/m

λ=8.85×10^-12C^2/Nm^2

r=(1.44×10^-10C/m)/(2(3.14)(8.85×10^-12C^2/Nm^2)(2.41N/C))

r=1.07m

At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.

To learn more about electric field refer the link:

brainly.com/question/12821750

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5 0

7 months ago

Help please! Thank you

Vesnalui [34]

Answer:

c

Explanation:

7 0

2 years ago

A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas

Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut $M_{1}$ = 60.0 kg

Mass of male astronaut $M_{2}$ = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = $\frac{G*M_{1}*M_{2}}{S^{2} }$

G = 6.67*10^-11 $\frac{m^{3} }{kg*s^{2} }$

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/ $M_{1}$ = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/ $M_{2}$ = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

$a_{average} = \frac{a_{1}+a_{2}}{2}$ = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2) where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0

2 years ago

Interestingly, there have been several studies using cadavers to determine the moments of inertia of human body parts, informati

Ugo [173]

Answer:

0.08821 kgm²

Explanation:

f = Frequency = 1.7 Hz

m = Mass of lower leg = 5.7 kg

d = Distance of center of mass = 18 cm

g = Acceleration due to gravity = 9.81 m/s²

I = Moment of inertia

Frequency is given by

$f=\frac{1}{2\pi}\sqrt{\frac{mgd}{I}}\\\Rightarrow I=\frac{mgd}{(2\pi f)^2}\\\Rightarrow I=\frac{5.7\times 9.81\times 0.18}{(2\pi 1.7)^2}\\\Rightarrow I=0.08821\ kgm^2$

The moment of inertia of the lower leg is 0.08821 kgm²

8 0

2 years ago

My predicted height was lower than the final height i measured. this is because friction slowed the puck as it was sliding along

LekaFEV [45]

I disagree since friction will cause the ultimate height to be lower than what was anticipated. To reduce the height, resist the action.

<h3> What is the height?</h3>

The vertical distance between an object's top and the bottom is defined as its height.

It is measured in centimeters, inches, meters, and other units. The height of the cliff is obtained by the Newton equation of motion.

My actual height was less than what I had anticipated. this is because the puck's movement along the track was impeded by friction.

To the Khalida, I object. Disagree, since friction will cause the ultimate height to be lower than the anticipated height. To reduce the height, resist the action.

Hence, I disagree with Khalida.

To learn more about the height, refer to the link;

brainly.com/question/10726356

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6 0

1 year ago