Explanation:
i1=1ampere
i1+i2=I
VA−VB=i1×3Ω=i2×6
⇒1×3=i2×6
2i=21ampere
Hence I=i1+i2=1+0.5=1.5ampere
Req=2+3+63×6=2+93×6=4Ω
equivalent circuit
Refer image .2
From KVL
1req=v
v=1.5×4
Answer:
1.25C
Explanation:
When capacitance is in series we add them like this: 1/Ctotal = 1/C1 +1/C2 + 1/C3.....
1/C = 1/2 + 1/5 + 1/10 = 5 + 2 + 1/10 = 8/10
C = 10/8 = 1.25
Capacitance = Charge/potential difference(Q/V)
1.25 = Charge/12
Total charge = 1.25 ×12 =15coulombs
Complete question is;
The place you get your hair cut has two nearly parallel mirrors 6.50 m apart. As you sit in the chair, your head is 3.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be?
Answer:
13 m
Explanation:
We are given;
Distance between two nearly parallel mirrors; d = 6.5 m
Distance between the face and the nearer mirror; x = 3 m
Thus, the distance between the back-head and the mirror = 6.5 - 3 = 3.5m
Now, From the given values above and using the law of reflection, we can find the distance of the first reflection of the back of the head of the person in the rear mirror.
Thus;
Distance of the first reflection of the back of the head in the rear mirror from the object head is;
y' = 2y
y' = 2 × 3.5
y' = 7
The total distance of this image from the front mirror would be calculated as;
z = y' + x
z = 7 + 3
z = 10
Finally, the second reflection of this image will be 10 meters inside in the front mirror.
Thus, the total distance of the image of the back of the head in the front mirror from the person will be:
T.D = x + z
T.D = 3 + 10
T.D = 13m
Longitudinal waves travel through a series of compressions and rarefactions.
The speed of the wave is given by Distance divided by time.
Speed = 10.9/5.1
= 2.14 m/s
But; speed is also given by frequency multiplied by wavelength
Wavelength is 4 m( distance between two successive crests)
thus; 2.14 = 4 × f
f = 2.14/4
= 0.535 Hz
