In order to understand this question, one needs to understand the construction first. After creating POQ, Meg picks a radius r and makes a circle around O. There are 2 points where the circle meets the triangle. Then, she meets another radius and she makes a circle of radius s around each of the points on the triangle. The two circles cross at one point, as can be seen in the figure. Let's name the first two points A and B and let's name the last point S. We have that for the triangles OAS, OBS we have OA=OB=r, BS=AS=s and that OS is common to both. Thus by the S-S-S triangle equality theorem, the triangles are equal. Hence for the angles AOS=BOS, namely POS=QOS. Since POQ=POS+QOS, we have that POS has to be half of POQ. The only consistent choice is the third one, POS=20 degrees and POQ=40 degrees.
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Given:
Radius of the base of the cone = 12 in.
The slant height of the cone = 15 in.
To find:
The lateral surface area of the given cone.
Solution:
The lateral surface area of the cone is:
Where, r is the radius of the base of the cone and h is the slant height of the cone.
Putting 
, we get
The lateral surface area of the cone is 180π in ² and the missing value for the blank is 180.
A) m=-3
B) n=-17
hope this helps x
would love to have brainliest if it is right :)
