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svetoff [14.1K]
3 years ago
8

20. A man invests $20,000 at an annual interest rate of 7%, and $ 12,000.00 at an

Mathematics
1 answer:
olganol [36]3 years ago
7 0

Answer:

The answer is (5.)2,800.00

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Can you please help me?
iren2701 [21]

Answer:

1 = 3

2 = 6

3 = 9

Step-by-step explanation:

for every # it is multiplied by 3 (ex. 7 • 3 = 21, 8 • 3 = 24, ect.)

therefore if it is multiplied by 3 each time

then 1 • 3 = 3

2 • 3 = 6

and 3 • 3 = 9

hope this helps :)

5 0
3 years ago
Read 2 more answers
5d-2/3c if d =4 and c =3 evaluate fast fast
Mademuasel [1]

Answer:

2

Step-by-step explanation:

Plug 4 in for d and 3 in for c

5d-2/3c

5(4)-2/3(3)

Multiply in the numerator and the denominator

20-2/9

Subtract in the numerator

18/9

2

Hope this helps! :)

4 0
3 years ago
(8p - 2) (6p+2) <br><br> help plz
qaws [65]

Answer:

48p^2+2p-4

Step-by-step explanation:

We can use the FOIL method to expand two multiplied binomials. It states that (a+b)(c+d)=ac+bc+ac+bd. The FOIL method stands for First(first terms) outer(outer terms) inner(inner terms) last(last terms).

So, we can expand our binomials now!

(8p-2)(6p+2)=(8p)(6p)-2(6p)+(8p)(2)-2(2)=48p^2-12p+14p-4=\boxed{48p^2+2p-4}

8 0
3 years ago
A crawling tractor sprinkler is located as pictured below, 100 feet South of a sidewalk. Once the water is turned on, the sprink
deff fn [24]

Answer:

  a) see below

  b) 32 minutes after turn-on

  c) 52 minutes after turn-on

  d) 20 minutes

  e) 6856.6 ft²

Step-by-step explanation:

a) We have elected to put the origin at the point where the hose crosses the south edge of the sidewalk. Units are feet. Then the sprinkler starts at (0, -100). After 1 hour, 3600 seconds, the sprinkler is 1800 inches, or 150 ft north of where it started, so stops at (0, 50).

The lines forming the sidewalk boundaries are y=0 and y=10.

__

b) Water will first strike the sidewalk when the sprinkler is 20 feet south of it, or 80 feet north of where it started. The sprinkler travels that distance in ...

  (80 ft)(12 in/ft)/(1/2 in/s)(1 min/(60 s)) = 32 min . . . time to start sprinkling sidewalk

__

c) The sprinkler has to travel to a point 130 ft north of its starting position for the water to fall north of the sidewalk. That distance is traveled in ...

  (130 ft)(2/5 min/ft) = 52 min . . . time until end of sprinkling sidewalk

Note that we have combined the scale factors in the expression of part b into one scale factor of (2/5 min/ft).

__

d) The difference of times in parts b and c is the time water falls on the sidewalk: 20 minutes.

__

e) In one hour, the sprinkler travels a distance of ...

  (60 min)(5/2 ft/min) = 150 ft

Of that distance, 10 feet is sidewalk. So, the sprinkler covers an area of grass that is a 140 ft by 40 ft rectangle and a circle of 20 ft radius. The total area of that is ...

  A = LW + πr² = (140 ft)(40 ft) +π(20 ft)² = (14+π)(400) ft² ≈ 6856.6 ft²

The area of grass watered in 1 hour is about 6856.6 ft².

5 0
3 years ago
Two brothers are saving money to buy tickets to a concert. their combined saving is $55 one brother has $15 more than the other.
Vladimir [108]

Brother one: x

Brother two: x + 15

---

Make them add up to 55 in an equation.

x + (x + 15) = 55

Combine like terms.

2x + 15 = 55

Subtract 15 from both sides.

2x = 40

Divide both sides by 2.

x = 20

Plug 20 for x into brother two.

(20) + 15 = 35

Brother one has saved $20, brother two has saved $35.

6 0
3 years ago
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