A line has a slope of 9/13 and passes through the point (13, 7). What is its equation in slope-intercept form?

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

y = 9/13x - 2

Step-by-step explanation:

y = 9/13x + b

7 = 9/13(13) + b

7 = 9 + b

-2 = b

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To make a profit, a company’s revenue must be greater than its operating costs. The company’s revenue is modeled by the expressi

valina [46]

Revenue = 7.5x - 100
Operation Costs = 5.8x + 79.86

To break even, operation cost = Revenue
⇒ 7.5x - 100 = 5.8x + 79.86
7.5x = 5.8x + 179.86 (Add 100 to both sides)

7.5x - 5.8x = 179.86
1.7x = 179.86
x = 105.8

This implies that the company will need to sell at least 106 items to make a profit.

The inequality that will determine the number of items at need to be sold to make a profit is x ≥ 106

The solution to the inequality is as follows

Revenue = 7.5x - 100
if x =106
Revenue = 7.5(106) - 100
Revenue = 695

Operational Cost = 5.8x + 79.86
if x = 106
Operational Cost = 5.8(106) + 79.86
Operational Cost = 694.66

Profit ≥ (695 - 694.66)
Profit ≥ 0.34

The company must sell at least 106 items to make a profit.

8 0

3 years ago

Read 2 more answers

Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.

alexdok [17]

Answer:

The probability is $\frac{1}{n}$

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

If k=1

$P = \frac{1}{n}$

Because, in her first try she has n possibles options and just one give her a successful login.

If k=2

$P=\frac{n-1}{n} *\frac{1}{n-1} =\frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.

If k=3

$P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.

Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n

7 0

3 years ago

PLEASE PLEASE PLEASE HELP ME

lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD: