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GuDViN [60]
3 years ago
14

[For Questions 1 & 2]

Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

B. 19 min 15 sec

B. 13 min 25 sec

Step-by-step explanation:

Door 1 opens every 1 min 45 sec, or 105 sec.

Door 2 opens every 1 min 10 sec, or 70 sec.

Door 3 opens every 2 min 55 sec, or 175 sec.

Door 4 opens every 2 min 20 sec, or 140 sec.

Door 5 opens every 35 sec.

The greatest common factor is 35 seconds, so we can measure the time in units of 35 seconds.

Door 1 opens every 3 units.

Door 2 opens every 2 units.

Door 3 opens every 5 units.

Door 4 opens every 4 units.

Door 5 opens every 1 unit.

The least common multiple of 3, 2, 5, 4, and 1, is 60.  So every 60 units, all five doors will open, and the guard will look down the corridor to check on the prisoner.  Douglas must escape before this time.

In order to escape in the shortest time possible, Douglas should time his escape so that each door opens 1 unit after the door before it.  It takes Douglas 20 seconds to move from one door to another, so he will have enough time to get to the next door before it opens.

Let's say Douglas starts moving when Door 1 opens for the nth time.  In other words, 3n units have passed before he starts moving.  That means Door 2 should open after 3n + 1 units.  Door 3 should open after 3n + 2 units.  Door 4 should open after 3n + 3 units.  And Door 5 should open after 3n + 4 units.

Since Door 2 opens every 2 units, 3n + 1 should be a multiple of 2.

Since Door 3 opens every 5 units, 3n + 2 should be a multiple of 5.

Since Door 4 opens every 4 units, 3n + 3 should be a multiple of 4.

Since Door 5 opens every 1 unit, 3n + 4 should be a multiple of 1.

By trial and error, n = 11.

So Douglas starts moving after 33 units, or 1155 seconds, or 19 min 15 sec.

Douglas clears the fifth door after 37 units, which leaves 23 units to spare, or 805 seconds, or 13 min 25 sec.

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Gage's math teacher entered the seventh-grade student in a math competition. There was an enrollment fee of $30 and also $11 cha
Amanda [17]

Answer:

110 test

Step-by-step explanation:

Let

x ----> the number  of packet of 10 test

y ----> the total cost

we know that

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so

The linear equation that represent this scenario is

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we have

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substitute

151=11x+30

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subtract 30 both sides

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Divide by 11 both sides

x=11

The number of packets purchase was 11

To find out the number of test, multiply the number of packets by 10

11(10)=110\ test

4 0
3 years ago
Find the missing side. Round your answer to the nearest hundredth.<br> х<br> 28°<br> 42 in<br> in
sleet_krkn [62]

Answer:

The length of the missing side x = 47.57 in    

Step-by-step explanation:

Given

Ф = 28°

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The hypotenuse x = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

substitute adjacent = 42 in, hypotenuse = x and Ф = 28°

cos 28° = 42 / x

x = 42 / cos 28°

x = 47.57 in      

Therefore, the length of the missing side x = 47.57 in    

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A circle has its center at the origin, and (5, -12) is a point on the circle. How long is the radius of the circle?
aivan3 [116]
Hello here is a solution :
<span> the radius of the circle is OA        A(5;-12) and O (0;0)
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7 0
3 years ago
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Mariana [72]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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