A standard form equation has mutually prime integers for coefficients, and the leading one is positive. We can get that here by multiplying by 3 (to eliminate the denominator) and dividing by 2 (to remove that common factor). The result is ...

4(3/2)x -(2/3)(3/2)y = 8(3/2)

6x -y = 12

6 0

2 years ago

What is the quadratic formula?

Ne4ueva [31]

Answer:

I guess u want to know the quadratic function and its formula is, AX*2 + BX + C. Otherwhise you want to know how to get 0 and get the Xm if you want to know how to solve a quadratic. That formula is, (-B +/- $\sqrt{x}$ (B*2 - 4AC) ) . 1/2 (where A, B and C are the number at the original function).

Step-by-step explanation:

6 0

2 years ago

Find the sum of the following series. Round to the nearest hundredth if necessary,

Aneli [31]

Answer:

$sum = \frac{a( {r}^{n - 1} )}{r - 1} \\ : but \: l = a( {r}^{n - 1} ) \\ 49152 = 3( {2}^{n - 1} ) \\ 16384 = {2}^{n - 1} \\ {2}^{n} = 32768 \\ {2}^{n} = {2}^{15} \\ n = 15 \\ \therefore \: sum = \frac{3(2 {}^{15 - 1}) }{15 - 1} \\ = \frac{49152}{14} \\ = 3510.9$

3 0

3 years ago