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Brilliant_brown [7]
3 years ago
13

Required nutrients in foods that are made by other living organisms are_______

Chemistry
1 answer:
Mazyrski [523]3 years ago
5 0

Answer: Vitamins

Explanation:

they are nutrients that are made by living things

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List three branches life<br>Science and describe what studied in each?​
Mama L [17]

Answer:

First off Life sciences are anything concerned with the study of a living organisms. So ones that would be included would be, microbiology biology, botany, zoology, ecology, genetics and medicine, from what the dictionary states

Explanation:

Biology is the natural science that studies life and living organisms. Which also includes molecular interactions, including their physical structure.

Genetics, is the study of heredity and or the variation of inherited characteristics that we get from family.

Microbiology, is the branch of science which deals with microorganisms.

Let me know if this helps, if not I'll continue researching.

3 0
3 years ago
This image shows electronegativities of elements on the periodic table. Based on this information, which element is most likely
andrezito [222]

Answer:

helium

Explanation:

7 0
3 years ago
85% of what number is 17? EXPLAIN
vitfil [10]

Answer:

85% of 20 is 17

Explanation:

You can multiply 85% and 20 or subtract 85% from 20.

5 0
3 years ago
Stable nuclei with low atomic numbers, up to 20, have a neutron to proton ratio of approximately ________.
Pie
1 to 1. Most small atoms have the same number of protons and neutrons
6 0
4 years ago
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

4 0
3 years ago
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