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aleksandrvk [35]
3 years ago
11

At the midpoint of a titration curve ________. At the midpoint of a titration curve ________. The concentration of a conjugate b

ase is twice that of the concentration of a conjugate acid The pH equals the pKa The ability of the solution to buffer is at its least effective The concentration of a conjugate base is 1/2 that of the concentration of a conjugate acid
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

The concentration of a conjugate base is twice that of the concentration of a conjugate acid

Explanation:

This is because at the midpoint, the number of moles of acid equals half the number of moles of base at the midpoint. This means that at the midpoint, half the analyte has been titrated.

Since the concentration of the conjugate acid is half that of the conjugate base at the midpoint, this implies that the concentration of the conjugate base is twice that of the conjugate acid.

<u>Thus, at the midpoint of a titration curve the concentration of a conjugate base is twice that of the concentration of a conjugate acid </u>

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When solid Ni metal is put into an aqueous solution of Sn(NO3)2, solid Sn metal and a solution of Ni(NO3)2 result. Write the net
Monica [59]

Answer:

Ni + Sn^2+ —> Sn + Ni^2+

Explanation:

First let us generate an elemental equation for the reaction. This is illustrated below:

Ni + Sn(NO3)2 —> Sn + Ni(NO3)2

From the equation above, a solid metal Sn is formed.

Now we can generate a net ionic equation as follows:

Ni + Sn^2+ —> Sn + Ni^2+

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3 years ago
How many covalent bonds can Carbon, Hydrogen, Nitrogen, Or Oxygen form?
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Hydrogen can form one covalent bond.
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3 years ago
How many grams of oxygen can be obtained from 250. grams of KCIO3?
guapka [62]

Answer:

Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.

Explanation:

3 0
2 years ago
What is the mass, in grams, of 50.0L of N2 at STP?
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Hey there!:

Molar mass N₂ = 28.0134 g/mol

28.0134 g ------------------- 22.4 L (at STP )

mass  N₂ -------------------- 50.0 L

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Hope this helps!

6 0
3 years ago
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