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dimulka [17.4K]

3 years ago

14

the temperature in Moscow was 2 degrees Celsius then it dropped to 8 degrees Celsius below zero by how many degrees did the temp

erature drop

1 answer:

levacccp [35]3 years ago

3 0

Answer:

11

Step-by-step explanation:

2-8 you need to minus the first number

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If the difference when −15 is subtracted from a number is twice the difference when 24 is subtracted from the same number, what

kirill [66]

Answer:

The number is 39

Step-by-step explanation:

Let the unknown number be <em>x</em>:

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4 0

3 years ago

at noon on monday the temperature was 13°f.by 6:00 pm,the temperature had dropped 9 degrees.by midnight the temperature had drop

MissTica

Answer:

-3°

Step-by-step explanation:

if you subtract 9 for 13 ,, you get 4

then when you subtract 7 from 4 it goes into the negative side and gets you negative 3 degrees

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3 years ago

Now simplify the y-terms to get the equation of the parabolic path. You do not need to expand the x-term. (2 points) Hint: Squar

aalyn [17]

The simplified equation of $(x - 10)^2 + (y- 6)^2 = 4^2$ is $y = 6+ \sqrt{16 - (x - 10)^2}$

<h3>How to determine the simplified equation?</h3>

The complete question is added as an attachment

The equation is given as

$(x - 10)^2 + (y- 6)^2 = 4^2$

Subtract (x - 10)^2 from both sides

$(y- 6)^2 = 4^2 - (x - 10)^2$

Evaluate 4^2

$(y- 6)^2 =16 - (x - 10)^2$

Take the square root of both sides

$y- 6= \sqrt{16 - (x - 10)^2}$

Add 6 to both sides

$y = 6+ \sqrt{16 - (x - 10)^2}$

Hence, the simplified equation of $(x - 10)^2 + (y- 6)^2 = 4^2$ is $y = 6+ \sqrt{16 - (x - 10)^2}$

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brainly.com/question/723406

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B is the answer to your question

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago