Find the area of the triangle <br><br> Area of triangle

How can the associative property be used to mentally solve 48+82?

Lilit [14]

(40+80) + (8+2)
120+10
130
your answer would be 130
you group 40 and 80 and get the answer and then group 8 and 2
get answer to both then and then you add them together for the answer

5 0

3 years ago

Please help me and ill mark you as brainlest ;)!

JulsSmile [24]

The hypotenuse would be 9 inches as 6 is equal to 2/3 of 9 :)

6 0

3 years ago

Use Order of Operations to simplify the following:

allochka39001 [22]

Answer:

where is simplify question

7 0

3 years ago

A circuit has a current of 1.2 a. if the voltage decreases to one-third of its original amount while the resistance remains cons

Alexeev081 [22]

Given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = IR

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Initially, A circuit has a current I = 1.2A

V = IR

R = V/I

R = V/1.2A ...... let this be equation 1

Next, voltage decreases to one-third of its original amount while the resistance remains constant.

Meaning Voltage = 1/3 of V = V/3

Hence;

V = IR

V/3 = IR

From equation 1 ( R = V/1.2A )

V/3 = I × V/1.2A

V/3 = IV/1.2A

We cross multiply

V1.2A = 3IV

I = V1.2A / 3V

I = 1.2A / 3

I = 0.4A

Therefore, given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

Learn more about potential difference here: brainly.com/question/2364325

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8 0

2 years ago

Read 2 more answers

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

1 year ago

Find the area of the triangle Area of triangle