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Triss [41]
2 years ago
13

When a number is halved and 5 is added, the result ie 8 more than the original number. Find the number​

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer:

It would be 6.

Step-by-step explanation:

6 halved is 3.

3, then 5 added is 8.

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     Brandon is 6 times as old as Cora. In 4 years, Brandon will be only twice as old as
nalin [4]
C-Cora's\ age\ now\\B-Brandon's\ age\ now\\\\B=6C\ \ \ and\ \ \ B+4=2(C+4)\\\\6C+4=2C+8\\6C-2C=8-4\\4C=4\ \ \ \Rightarrow\ \ \ C=1\ \ \ \Rightarrow\ \ \ \ B=6\cdot1=6\\\\Ans.\ Brandon\ is\ now\ 6\ years.
4 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
3 years ago
A birthday celebration meal is $46.80 including​ tax, but not the tip. find the total cost if a 10% tip is added to the cost of
irina1246 [14]
$51.48 should be the answer
8 0
3 years ago
PLEASE HURRY , 30 PTS !!!!
Keith_Richards [23]

a = v^2 / r

v^2 = ar

v = √ar

8 0
3 years ago
Read 2 more answers
Solve for X: 5x + 15 = 28
rjkz [21]
-15 both sides and then it’s will be
5x = 13 then u divide both sides over 5 and the answer will be ( X=2.6 )
4 0
2 years ago
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