Answer:
The distance covered by the body is, S = 800 m
Explanation:
Given data,
The initial velocity of the body, u = 30 m/s
The acceleration of the body, a = 10 m/s²
Let the time period of travel be, t = 10 s
Using the II equations of motion,
S = ut + ½ at²
Substituting the given values,
S = 30 x 10 + ½ x 10 x 10²
S = 800 m
Hence, the distance covered by the body is, S = 800 m
Answer:
<em>The mass of the shotput is 7.37 Kg.</em>
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).
A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.
It can be done by solving the equation for m:
Substituting the given values:
m = 7.37 Kg
The mass of the shotput is 7.37 Kg.
Hi there!
Recall the equation for Torque:
In words, the torque is the force multiplied by the distance from the LINE OF ACTION to the PIVOT POINT.
In this instance:
F = Mg = 0.75 · 9.8 = 7.35 N
r = 1.25 m
sin(30) = 0.5
Plug in the values: