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iVinArrow [24]
2 years ago
13

Why did astronomers suspect an eighth planet beyond uranus? how did they determine where to look for it? construct the correct e

xplanation.
drag the terms on the left to the appropriate blanks on the right to complete the sentences.

brightness - mass - orbit - position - kepler's third law - value - law of gravity


observation of uranus showed small but significant discrepancy between its predicted ______ and its actual ________ , which could mean that another object perturbed its motion.
in the mid-1800s, astronomers used the ________ to predict where a planet would have to be.
Physics
1 answer:
DerKrebs [107]2 years ago
7 0

Astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.

<h3>Who is an astronaut?</h3>

It should be noted that an astronaut simply means an individual who is trained to travel in spacecrafts.

In this case, astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.

In mid-1800s, astronomers used the orbits of most asteroids to predict where a planet would have to be.

Learn more about astronaut on:

brainly.com/question/2314879

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A uniform meter stick of mass $M$ has a half-filled can of fruit juice of mass $m$ attached to one end. The meter stick and the
notka56 [123]

Answer:

111.6 g

Explanation:

Given

m + M = 2.58 / 9.8

= 0.2632 kg

When the can of fruit juice is balance from scale , we get following relation

M x ( 50 - 21.2 ) = m x 21.2 ( balancing the torque due to weight of scale and can about the balancing point )

M x 28.8 = 21.2 m

= 21.2 ( 0.2632 - M )

= 5.58 - 21.2 M

M ( 28.8 + 21.2 ) = 5.58

M = .1116 kg

= 111.6 g

7 0
3 years ago
A sled whose total mass with cargo is 30.0 kg rests on ice. The coefficient of static friction is 0.20 and the coefficient of ki
romanna [79]

when sled just start to move the force on the sled will be equal to the static friction

So here we need to find the value of static friction

We know that

m = 30 kg

\mu_s = 0.20

now we know that normal force on the block is counterbalanced by weight of the block

F_n = mg

F_n = 30*9.8

now in order to find the friction force we can use

F_s = \mu_s * F_n

F_s = 0.20 * 30 * 9.8

F_s = 59 N

so it requires 59 N of force to move the sled

5 0
3 years ago
In which arrangement of magnets will all the magnets attract?
Orlov [11]

Answer:

B

Explanation:

opposites attract ;)

8 0
4 years ago
How can a small boy balance a big boy<br>on asea- saw ? Show with a diagram​
liq [111]

Answ

— How can a small boy balance a big boy on a sea-saw? Show with a diagram. fast please...... Get the answers you need, now!

2 answers

Images for How can a small boy balance a big boy on seesaw ? Show with a diagram​

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Explanation:

4 0
3 years ago
A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee
andrey2020 [161]

(a) 2.56\cdot 10^4 J

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

E=2.56\cdot 10^4 J

Therefore we can set up a simple proportion

1 cal : 4186 J = x : 2.56\cdot 10^4 J

to find the equivalent energy in calories:

x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal

3 0
3 years ago
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