Three individual point charges are placed at the following positions in the x-y plane:Q3= 5.0 nC at (x, y) = (0,0);Q2= -3.0 nC a
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Answer:
(a). The magnitude of the net force is
(b). The magnitude of the net force is
(c). The magnitude of the net force is
Explanation:
Given that,
Magnetic field
Velocity = 2230j m/s
We know that,
The net force acting on the proton is equal to the sum of electric and magnetic force.
(a). If the electric field is in the positive z direction and has a magnitude of 5.25 V/m,
We need to calculate the magnitude of the net force acting on the proton
Using formula of net force
Put the value into the formula
(b). If the electric field is in the negative z direction and has a magnitude of 5.25 V/m,
We need to calculate the magnitude of the net force acting on the proton
Using formula of net force
Put the value into the formula
(c). If the electric field is in the positive x direction and has a magnitude of 5.25 V/m
We need to calculate the magnitude of the net force acting on the proton
Using formula of net force
Put the value into the formula
Hence, (a). The magnitude of the net force is
(b). The magnitude of the net force is
(c). The magnitude of the net force is