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Usimov [2.4K]
3 years ago
10

You are writing a report about space travel. Where would be the best place to find information? (2 points)

Physics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

Contact NASA about space travel

Harrizon [31]3 years ago
5 0

Answer: Contact the National Aeronautics and Space Association

Explanation:

The National Aeronautics and Space Association is an independent organization in US which aims to enable a safe, secure, efficient space journey and launch of new satellites, spacecraft beyond the earth's orbit. It can give better information for the space travel already conducted by the astronauts. Thus will help in writing the report as it is the best place to find the information.  

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High energy waves have short wave lengths, true or false?
Anna71 [15]
True, the wavelength dies down due to high frequency and low amptitude. 
5 0
3 years ago
Question 2
Delvig [45]

Answer:

Approximately 73\; {\rm N}, assuming that the acceleration of this ball is constant during the descent.

Explanation:

Assume that the acceleration of this ball, a, is constant during the entire descent.

Let x denote the displacement of this ball and let t denote the duration of the descent. The SUVAT equation x = (1/2)\, a\, t^{2} would apply.

Rearrange this equation to find an expression for the acceleration, a, of this ball:

\begin{aligned} a &= \frac{2\, x}{t^{2}}\end{aligned}.

Note that x = 11\; {\rm m} and t = 1.5\; {\rm s} in this question. Thus:

\begin{aligned} a &= \frac{2\, x}{t^{2}} \\ &= \frac{2 \times 11\; {\rm m}}{(1.5\; {\rm s})^{2}} \\ &\approx 9.78\; {\rm m \cdot s^{-2}}\end{aligned}.

Let m denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is a, the net external force on this ball would be m\, a.

Since m = 7.5\; {\rm kg} and a \approx 9.78\; {\rm m\cdot s^{-2}}, the net external force on this ball would be:

\begin{aligned} (\text{net force}) &= m\, a \\ &\approx 7.5\; {\rm kg} \times 9.78\; {\rm m\cdot s^{-2}} \\ &\approx 73\; {\rm kg \cdot m \cdot s^{-2} \\ &= 73\; {\rm N} && (1\; {\rm N} = 1\; {\rm kg \cdot m\cdot s^{-2}}) \end{aligned}.

4 0
2 years ago
1. A runner drops her phone as she is running at a constant speed of 3 miles per hour from point A to point B in a park. Describ
joja [24]

Answer:

Let's define the point A as our zero in the x-axis.

As the phone drops, it keeps the horizontal velocity that it had before, so the horizontal velocity is:

Vx = 3 mi/h.

Now, the only force acting on the phone is the gravitational force that acts in the vertical axis, then we have:

Ay = -g

where g = 9.8 m/s^2

It is dropped, so we do not have a vertical initial velocity, then for the vertical velocity we should integrate over time:

Vy = -g*t

And for the position again, we integrate over time, but now we have an initial position H, that is the height at which the phone is dropped.

Py = -(1/2)*g*t^2 + H

And the horizontal position can be found by integrating over time the horizontal velocity.

Px = (3mi/h)*t

This will be the two equations that describe the motion of the phone, and we can not solve it further because we do not know the initial height of the phone.

But in general, we have a linear equation in the horizontal axis and a quadratic equation with a negative leading coefficient in the vertical axis.

Position(t) = ( (3mi/h)*t,  -(1/2)*g*t^2 + H)

5 0
3 years ago
You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction b
adell [148]

Answer:

c

Explanation:

The car travels with centripetal acceleration which is directed to the center of the circle but the velocity is changing since the car faces different direction as it travels in the circular direction. When the friction is zero between the tires of the car and the road, it will continue in the direction of its tangential velocity which will be along a straight-line path in its original direction.

4 0
3 years ago
"I help people adopt beneficial behaviors such as a balanced diet and exercise. I am a ______ psychologist." A. Rehabilitation B
Rama09 [41]

Answer:

health

Explanation:

rehabilitation focuses on people who come back from certain habits

development focuses on infants and kids behavior

community focuses on community problems

8 0
3 years ago
Read 2 more answers
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