Answer:
(A) = 2.13 s
(B) = 0.47 Hz
(C) = 0.25 m
(D) = 0.74 m/s
Explanation:
number of oscillations (n) = 15
time (t) = 32 secs
start point (L1) = 13 cm = 0.13 m
End point (L2) = 63 cm = 0.63 m
(A) period = time / number of oscillation
= 32 / 15 = 2.13 s
(B) frequency = 1 / period
= 1 / 2.13 = 0.47 Hz
(C) Amplitude = 0.5 ( L2 - L1 )
= 0.5 ( 0.63 - 0.13 )
= 0.25 m
(D) max speed = (2π / T) x A
= (2π / 2.13) x 0.25
= 0.74 m/s
The freezing point of water is 0 degree Celsius.
So as soon as the water’s temperature becomes 0 or anything lesser than that ,
It will become ice, which is the solid form of ice
Answer:

Explanation:
From the question we are told that:
Far point 
Refractive power 
Generally, the equation for Focal length is mathematically given by



Therefore

Where



Therefore,The between her glasses and eyes



Answer:
Explanation:
A) <em>Large</em>: As she opens her parachute, she begins to displace a large volume of air. This leads to a Large air resistance
B) <em>increase, weight</em>: As she falls, the air resistance force <u><em>increases</em></u>. Now there is a force acting in opposite directions to her <u><em>weight.</em></u>
C)<em>Weight, Decelerate:</em> The skydiver has only the downward force of her <u><em>weight</em></u> pulling down on her, so she starts to <u><em>decelerate</em></u>
D) <em>Weight, Upward, Resultant</em>:
Her <u><em>weight </em></u>is now equal to the <u><em>upward </em></u>force from the ground. Her <u><em>resultant </em></u>force is then zero
E) <em>Increases, same, constant, resultant, terminal</em>:
As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.
F) <em>Increases, same, constant, terminal</em>:
As she decelerates, the air resistance force on her parachute <u><em>increases </em></u>until it is the <u><em>same</em></u> as her weight. She is now moving with a <u><em>constant </em></u>speed until she hits the ground - a new slower <u><em>terminal</em></u> velocity
Answer:
Victor will always be able to select 4 of those cards with the following property
Explanation:
Number of trading cards = 100
victor selects 21 cards
let the 4 cards be labelled : A,B,C and D
The average power level of : A,B,C,D = ( A + B + C + D )/ 4 = P
let the two pairs be : ( A + B ) and ( C + D )
note: average power of each pair = P and this shows that
( A + B ) = ( C + D ) for Victor to select 4 cards out of the 21 cards that exhibit the same property
we have to check out the possible choices of two cards out of 21 cards yield distinct sums.
= C(21,2)=(21x20)/2 = 210.
from the question the number of distinct sums that can be created using 101 through 200 is < 210 .
hence it is impossible to get 210 distinct sums therefore Victor will always be able to select 4 of those cards