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Lisa [10]
3 years ago
9

How is force related to physics ?

Physics
2 answers:
NISA [10]3 years ago
6 0
I have no idea to be honest
il63 [147K]3 years ago
3 0

Answer:

In physics, a force is an influence that can change the motion of an object. A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate. ... A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of newton (N).

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An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 63.0 cm mark on the track. The glider compl
LuckyWell [14K]

Answer:

(A) = 2.13 s

(B) = 0.47 Hz

(C) = 0.25 m

(D) = 0.74 m/s

Explanation:

number of oscillations (n) = 15

time (t) = 32 secs

start point (L1) = 13 cm = 0.13 m

End point (L2) = 63 cm = 0.63 m

(A) period = time / number of oscillation

           = 32 / 15 = 2.13 s

(B) frequency = 1 / period

              = 1 / 2.13 = 0.47 Hz

(C) Amplitude = 0.5 ( L2 - L1 )

                           = 0.5 ( 0.63 - 0.13 )

                          = 0.25 m

(D) max speed = (2π / T) x A

                        =  (2π / 2.13) x 0.25

                       = 0.74 m/s

6 0
3 years ago
Water at -5°c in a solid explain ​
Zolol [24]
The freezing point of water is 0 degree Celsius.
So as soon as the water’s temperature becomes 0 or anything lesser than that ,
It will become ice, which is the solid form of ice
5 0
4 years ago
Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a
romanna [79]

Answer:

d=0.019m

Explanation:

From the question we are told that:

Far point x=0.759m

Refractive power P=-1.35 D.

Generally, the equation for Focal length is mathematically given by

F=\frac{1}{P}

F=\frac{1}{-1.35}

F=-0.74m

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Where

u=o

\frac{1}{-0.74}=\frac{1}{0}+\frac{1}{v}

v=-0.74m

Therefore,The between her glasses and eyes

d=x-v

d=0.759-0.74m

d=0.019m

4 0
3 years ago
I need the answers ASAP.
dsp73

Answer:

Explanation:

A) <em>Large</em>: As she opens her parachute, she begins to displace a large volume of air. This leads to a Large air resistance

B) <em>increase, weight</em>: As she falls, the air resistance force <u><em>increases</em></u>. Now there is a force acting in opposite directions to her <u><em>weight.</em></u>

C)<em>Weight, Decelerate:</em> The skydiver has only the downward force of her <u><em>weight</em></u> pulling down on her, so she starts to <u><em>decelerate</em></u>

D) <em>Weight, Upward, Resultant</em>:

Her <u><em>weight </em></u>is now equal to the <u><em>upward </em></u>force from the ground. Her <u><em>resultant  </em></u>force is then zero

E) <em>Increases, same, constant,  resultant, terminal</em>:

As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.

F) <em>Increases, same, constant, terminal</em>:

As she decelerates, the air resistance force on her parachute <u><em>increases </em></u>until it is the <u><em>same</em></u> as her weight. She is now moving with a <u><em>constant </em></u>speed until she hits the ground - a new slower <u><em>terminal</em></u> velocity

4 0
3 years ago
Victor has 100 trading cards, each with a distinct power level between 101 and 200 inclusive. Whenever he heads out, he always r
Alenkinab [10]

Answer:

Victor will always be able to select 4 of those cards with the following property

Explanation:

Number of trading cards = 100

victor selects 21 cards

let the 4 cards be labelled : A,B,C and D

The average power level of : A,B,C,D = ( A + B + C + D )/ 4 = P

let the two pairs be : ( A + B ) and ( C + D )

note: average power of each pair = P  and this shows that

( A + B ) = ( C + D ) for Victor to select 4 cards out of the 21 cards that exhibit the same property

we have to check out the possible choices of two cards out of 21 cards yield distinct sums.

= C(21,2)=(21x20)/2 = 210.

from the question the number of distinct sums that can be created using 101  through 200 is < 210 .

hence it is impossible to get 210 distinct sums therefore Victor will always be able to select 4 of those cards

4 0
4 years ago
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