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2 years ago

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Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a

refractive power of −1.35 D. Determine the distance between her glasses and eyes.

1 answer:

romanna [79]2 years ago

4 0

Answer:

$d=0.019m$

Explanation:

From the question we are told that:

Far point $x=0.759m$

Refractive power $P=-1.35 D.$

Generally, the equation for Focal length is mathematically given by

$F=\frac{1}{P}$

$F=\frac{1}{-1.35}$

$F=-0.74m$

Therefore

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

Where

$u=o$

$\frac{1}{-0.74}=\frac{1}{0}+\frac{1}{v}$

$v=-0.74m$

Therefore,The between her glasses and eyes

$d=x-v$

$d=0.759-0.74m$

$d=0.019m$

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2 years ago

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6 0

2 years ago

Can someone help me?!!!!!

german

<h2>Hello!</h2>

The answer is:

The first option, the walker traveled 360m more than the actual distance between the start and the end points.

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2 years ago

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2 years ago