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Rudik [331]
3 years ago
9

Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a

refractive power of −1.35 D. Determine the distance between her glasses and eyes.
Physics
1 answer:
romanna [79]3 years ago
4 0

Answer:

d=0.019m

Explanation:

From the question we are told that:

Far point x=0.759m

Refractive power P=-1.35 D.

Generally, the equation for Focal length is mathematically given by

F=\frac{1}{P}

F=\frac{1}{-1.35}

F=-0.74m

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Where

u=o

\frac{1}{-0.74}=\frac{1}{0}+\frac{1}{v}

v=-0.74m

Therefore,The between her glasses and eyes

d=x-v

d=0.759-0.74m

d=0.019m

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Russia shut off the Nord Stream pipeline that supplies natural gas to Germany.

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2 years ago
What is the equation that relate electric potential (voltage) to electric field?
erma4kov [3.2K]
V= I x R
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3 years ago
A disk 7.90 cm in radius rotates at a constant rate of 1 190 rev/min about its central axis. (a) Determine its angular speed. 12
Tanya [424]

Answer:

124.62\ \text{rad/s}

3.71\ \text{m/s}

1.23\ \text{km/s}^2

20.28\ \text{m}

Explanation:

r = Radius of disk = 7.9 cm

N = Number of revolution per minute = 1190 rev/minute

Angular speed is given by

\omega=N\dfrac{2\pi}{60}\\\Rightarrow \omega=1190\times \dfrac{2\pi}{60}\\\Rightarrow \omega=124.62\ \text{rad/s}

The angular speed is 124.62\ \text{rad/s}

r = 2.98 cm

Tangential speed is given by

v=r\omega\\\Rightarrow v=2.98\times 10^{-2}\times 124.62\\\Rightarrow v=3.71\ \text{m/s}

Tangential speed at the required point is 3.71\ \text{m/s}

Radial acceleration is given by

a=\omega^2r\\\Rightarrow a=124.62^2\times 7.9\times 10^{-2}\\\Rightarrow a=1226.88\approx 1.23\ \text{km/s}^2

The radial acceleration is 1.23\ \text{km/s}^2.

t = Time = 2.06 s

Distance traveled is given by

d=vt\\\Rightarrow d=\omega rt\\\Rightarrow d=124.62\times 7.9\times 10^{-2}\times 2.06\\\Rightarrow d=20.28\ \text{m}

The total distance a point on the rim moves in the required time is 20.28\ \text{m}.

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In this question all required information's are already provided. Based on these details the answer to the question can be easily determined. Let us now write down all the information's that are already given.

Mass of the roller coaster = 1000 kg

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We know the formula for finding the kinetic energy is

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So the Kinetic energy of the roller coaster is 200000 joules.

i hope this helps you friend good luck on your quiz or lesson

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