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2 years ago

12

A veterinarian thinks that a dog has swallowed a key ring. Which types of electromagnetic waves is the doctor most likely to use

to check the dog?

2 answers:

Roman55 [17]2 years ago

4 0

Answer:

The vet must use X-rays.

oee [108]2 years ago

3 0

Answer:

D x-rays

Explanation:

uses thermal image to see inside the dog.

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Conduction can only happen when objects are in:

serious [3.7K]

Answer:

When it’s gravitational

Explanation:

I’m pretty sure that’s the answer

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2 years ago

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What is one behavior that a plant has that a human would be suprised by

statuscvo [17]

Growing and being able to pollen

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2 years ago

A rolling ball with a mass of 1.01 kg crashes into a wall. The wall exerts a force of 2.40 Newtons and stops the ball. What was

klemol [59]

Answer:

Acceleration, a = 2.38m/s²

Explanation:

Given the following data;

Mass = 1.01 kg

Force = 2.4N

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration, a = \frac{F}{m}$

Substituting into the equation, we have;

$Acceleration, a = \frac{2.4}{1.01}$

<em>Acceleration, a = 2.38m/s²</em>

<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>

3 0

2 years ago

What parts of the body can be affected by musculoskeletal disorders?

adoni [48]

Answer:

Musculoskeletal disorders (MSD) are injuries or disorders of the muscles, nerves, tendons, joints, cartilage, and spinal discs.

Explanation:

3 0

2 years ago

To construct an oscillating LC system, you can choose from a 11 mH inductor, a 6.0 μF capacitor, and a 4.2 μF capacitor. What ar

Free_Kalibri [48]

Answer:

a. 475.14 Hz

b. 1959 Hz

c. 2341.53 Hz , 3053.34 Hz

Explanation:

$f = \frac{1}{2\pi*\sqrt{C*L}}$

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF replacing:

$f = \frac{1}{2\pi*\sqrt{C*L}}f=\frac{1}{2\pi*\sqrt{10.2uF*11mH}}$

$f = 475.14 Hz$

b. second smallest use the capacitive 6 uF so:

$f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{6uF*11mH}}$

$f = 1959Hz$

c. second largest and largest oscillation first combination so:

Use 4.2 uF

$f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{4.2uF*11mH}}$

$f = 2341.53 Hz$

And finally largest oscillation cap in serie so:

$C=\frac{c_1*c_2}{c_1+c_2}=\frac{4.2uF*6.0uf}{4.2uf+6.0uF}$

$C=2.47 uF$

$f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{2.47uF*11mH}}$

$f = 3053.34 Hz$

5 0

2 years ago