Ask question

Ask question

All categories

2 years ago

7

If a train conductor is describing the speed of the train as well as the direction the train is going, then the train conductor

is said to be describing the train's

1 answer:

natita [175]2 years ago

5 0

Then, train conductor is said to be describing the train's VELOCITY........

You might be interested in

An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object's position from the top of the

Lena [83]

Answer:

After 1 sec = 4.9 m

After 2 sec = 19.6 m

After 3 sec = 44.1 m

After 4 sec = 78.4 m

After 5 sec = 122.5 m

Explanation:

After 1 sec:

<em>u=0m/s t=1 s a=9.8m/s²</em>

s = ut + (1/2)at²

=0(1) + (1/2)(9.8)(1²) = 4.9m

After 2 sec:

<em>u=0m/s t=2 s a=9.8m/s²</em>

s = ut + (1/2)at²

=0(2) + (1/2)(9.8)(2²) = 19.6m

After 3 sec:

<em>u=0m/s t=3 s a=9.8m/s²</em>

s = ut + (1/2)at²

=0(3) + (1/2)(9.8)(3²) = 44.1m

After 4 sec:

<em>u=0m/s t=4 s a=9.8m/s²</em>

s = ut + (1/2)at²

=0(4) + (1/2)(9.8)(4²) = 78.4m

After 5 sec:

<em>u=0m/s t=5 s a=9.8m/s²</em>

s = ut + (1/2)at²

=0(5) + (1/2)(9.8)(5²) = 122.5m

7 0

2 years ago

An example of a single displacement reaction is

g100num [7]

Single Displacement Reaction Definition. A single displacement reaction is a chemical reaction where one reactant is exchanged for one ion of a second reactant. It is also known as a single replacement reaction.

6 0

3 years ago

Read 2 more answers

In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit

ivolga24 [154]

Answer:

$m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg$

Explanation:

The football players collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V=1.6m/s.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision, at the initial point the receiver does not have any speed

$m_{tackler}*v_{tackler}=(m_{tackler}+m_{receiver})V$ (1)

We solve in order to find the receiver mass:

$m_{receiver}={m_{tackler}*v_{tackler}/V}-m_{tackler}$

$m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg$

5 0

3 years ago

Two substances, M and N, have specific heats c and 2c. if heats Q and 4Q are supɔlied to Mand N, respectively, their changes in

Ierofanga [76]

Answer:

If the mass of B is m and the temperature change is the same, the mass of B will be 2m.

Explanation:

Q = mcT

T = mc/Q

M = 4Q/2cT........... (1)

T = Q/mc

Plug this in equation 1.

M = 4Q/(2c × Q/mc) = 4Q ÷ 2Q/m = 4Q × m/2Q = 2m

6 0

2 years ago

The rate of cooling determines ....... and ......

PilotLPTM [1.2K]

Answer:

freezing point and melting point

7 0

2 years ago