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cupoosta [38]
2 years ago
5

Explain what happens to the average kinetic energy, thermal energy, and temperature of a substance when the particles in the sub

stance slow down.
Physics
2 answers:
mamaluj [8]2 years ago
8 0

When particles in a substance slow down, we can infer that the object is getting colder. Why we can infer this:

1. Kinetic energy, is energy due to motion, therefore if there is no motion, there is no kinetic energy.  

2. The colder an object get, the closer it becomes to having it's particles stopping completely, eventually at the absolute zero.  

3. As kinetic energy increases, particles  move faster. Kinetic energy usually increases when an object gets warmer. As kinetic energy decreases, particles move slower. Kinetic energy usually decreases when an object gets colder.  

So, with this information, we now how and why the kinetic energy slows down.

Mekhanik [1.2K]2 years ago
7 0

Explanation:

The particles in a substance slow down when the average kinetic energy of the particles decreases. As the average kinetic energy decreases, the internal energy decreases, and so the thermal energy decreases. As the thermal energy of the substance decreases, the temperature decreases.  

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DanielleElmas [232]

Answer:

0.872<em>m/s</em>

Explanation:

Tangential velocity is given by the formula,

v= 2\pi r/ t

In the question given,

radius= 25meters

time= 180secs

pie= 3.14

number of laps= 1

The magnitude of tangential velocity equals;

\frac{1lap* 2 *3.14 *25m}{180secs}

<em>v </em>= 157<em>m</em>/180<em>secs</em>

Therefore, the magnitude of the tangential velocity

=0.872<em>m/secs</em>

5 0
2 years ago
A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg,
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6 0
2 years ago
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ExtremeBDS [4]
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2 years ago
The total capacitance of two 15uF capacitors<br> connected in parallel is
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7 0
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Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is
Reil [10]

Explanation:

Relation between potential energy and charge is as follows.

           U = qV

or,    \Delta U = q \times \Delta V

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