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OlgaM077 [116]
4 years ago
13

Given: m∠AEB = 45° ∠AEC is a right angle. Prove: bisects ∠AEC.

Mathematics
1 answer:
Musya8 [376]4 years ago
5 0
If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
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Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
a traveler has 7 pieces of luggage . how many ways can the traveler select 3 pieces of luggage for a trip
7nadin3 [17]
Well, you could assign a letter to each piece of luggage like so...

A, B, C, D, E, F, G

What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.

My answer and workings are below...

35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.

210 arrangements (35 x 6) when order is taken into consideration.

*There are 6 ways to configure 3 letters.

Alternative way to solve the problem...

Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.

7 0
3 years ago
if each side of a square classroom is 25 feet then what is the perimeter of the room? what is the area of the floor of the room?
Svetllana [295]

Answer:

P = 100

Area = 625

Step-by-step explanation:

Area = s^2

sqrt(area) =  sqrt(s^2)

area = 25*25

sqrt(25*25) = sqrt(s^2)

s = 25

P = 4*s

P = 4 * 25

P = 100

Area = s^2

s = 25

Area = 25^2

Area = 625

4 0
3 years ago
Peaches are being sold for $2 per pound. If x represents the number of pounds of peaches bought and y represents the total cost
Mama L [17]
2X=Y

2 because it is two dollars per pound.
8 0
3 years ago
Read 2 more answers
How can you write 2,000 in a exponent
Mnenie [13.5K]
1,000 = 10^3            (3 because there are 3 digits after the first one)

2,000 = 2 * 10^3
3 0
3 years ago
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