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s2008m [1.1K]
3 years ago
5

Can somebody please help mee!!!!

Mathematics
2 answers:
olga55 [171]3 years ago
5 0

Answer:

first \: w \: do \\  \\ 180 - 154 \\  \\  = 26 \\  \\ second \: we \: do \:  \\  \\ x + 10 + x + 26 = 180 \\  \\ 2x + 36 = 180 \\  \\ 2x = 180 - 36 \\  \\2 x = 144 \\  \\ x =  \frac{144}{2}  \\  \\ x = 72

koban [17]3 years ago
3 0

Answer:

  • x = 72

Step-by-step explanation:

<u>The exterior angle is the sum of non-adjacent interior angles:</u>

  • x + x + 10 = 154
  • 2x = 154 - 10
  • 2x = 144
  • x = 144/2
  • x = 72

The other interior angle is 82°

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Easiest way to calculate 22% mark up from a cost of say 39.99
satela [25.4K]

Answer:

The markup amount on the cost 39.99 $ will be: 8.78 $

Step-by-step explanation:

Given

  • The cost = 39.99 (Let say in $)
  • Mark up = 22%

As

22% = 0.22

The markup of 22% on the cost can be calculated by multiplying the cost by 22% or 0.22

so

Markup amount = 0.22 × 39.99

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Therefore, the markup amount on the cost 39.99 $ will be: 8.78 $

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3 years ago
How is the graph of y = 8x2 − 1 different from the graph of y = 8x2?
dezoksy [38]

Answer:

The first image = y =8x^2 -1

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Step-by-step explanation:

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3 years ago
Evaluate the expression when x = 4.
gulaghasi [49]
We have 3*4+2, or 14, by substituting in for x.
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3 years ago
A function is given: f (x) = 2x + 3<br> What is the value of f(-2)?
Nadusha1986 [10]

Answer:

f(-2) = -1

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-2 is x, so replace x as -2 into the equation

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3 years ago
Use the product property of roots to choose the expression equivalent to 3√5x*3√25x^2?
nignag [31]

Answer: \sqrt[3]{125x^3}.


Step-by-step explanation: Given radical expression

\sqrt[3]{5x} \times \sqrt[3]{25x^2}.

According to the product property of roots.

\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}

On applying above rule, we get

\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}

5 × 25 = 125 and

x \times x^2 = x^3

Therefore,

\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}

<h3>So, the correct option would be second option \sqrt[3]{125x^3}.</h3>

3 0
3 years ago
Read 2 more answers
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