3.125 would be the answer hope this helps
Answer:
The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.
Step-by-step explanation:
A confidence interval has two bounds, a lower bounds and an upper bound.
These bounds depend on the sample mean and the margin of error.
The lower bound is the sample mean subtracted by the margin of error.
The upper bound is the margin of error added to the sample mean.
In this problem, we have that:
The sample mean is $43.
The margin of error is $1.60 for a 99% confidence interval.
Lower bound: 43 - 1.60 = $41.40
Upper bound: 43 + 1.60 = $44.60
The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.
Answer:
1. No.
Since f(1)=f(3) and 
then f isn't one-to-one.
2. No
Since f(0)=f(2) and 
then f isn't one-to-one.
3. No
Since f(0)=f(2) and then f isn't one-to-one.
4. Yes
Since 
, then f is one-to-one
5. Since f(1)=f(3) and then, f isn't one-to-one
The equation that describes the number of tickets Rudolph can buy will be 25r + 10g = 150.
- Let the reserved tickets be represented by r.
- Let the general admission be represented by g.
Therefore, the equation will be 25r + 10g = 150.
The number of tickets that Rudolph can buy if he buys only reserved seat tickets will be:
= $150 / $25 = 6
The number of tickets that Rudolph can buy if he buys only general admission tickets will be:
= $150 / $10 = 15
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