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ipn [44]
3 years ago
12

Solve the inequality 16 – 7a ≥ –33. i will mark you brainliest!

Mathematics
2 answers:
Serhud [2]3 years ago
4 0

16 - 7a > (or equal to) -33

+16 +16


-7a > -17

÷7 ÷7


a > (or equal to) -2. 4

steposvetlana [31]3 years ago
3 0

16-7a>-33

-16       -16

-7a>-49

A<7

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Find two consecutive odd integers whose product is 899
UNO [17]

Answer:

Step-by-step explanation:

Let two consecutive odd numbers

x, x+2

According to condition

X(x+2) = 899

x2 +2x -899=0

X2 +31x -29x -899=0

x(x+31) -29(x+31)=0

(x+31)(x-29)=0

X=-31 or x =29

Now,

X=29

X+2= 29+2 = 31

Two consecutive odd numbers is 29 and 31

6 0
3 years ago
All parallelograms are _______
KengaRu [80]

Answer:

b) trapezoids

Step-by-step explanation:

a trapezoid has atleast one pair of opposite parallel sides

8 0
3 years ago
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0
3 years ago
1.17375 rounded to nearest tenth​
Elden [556K]

Answer:

1.2

Step-by-step explanation:

Since we are rounding it by the tenth, it means we are rounding to the 1st digit to the right of the decimal.

We know 7 is greater then 5 meaning we round up

.1 + .1 is equal to .2 meaning its 1.2

If you still don't understand, I recommend you talk to your teacher

5 0
2 years ago
Read 2 more answers
Hello im new here can anyone please answer this thank you!​
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